Manipur Board 2025 Class 12 Syllabus: The syllabus is an integral part of every student’s life. The Council of Higher Secondary Education, Manipur (COHSEM) designs...
Manipur Board Class 12 Syllabus 2025: Subject-wise PDF Download
November 17, 2024A well-defined collection of objects or elements is known as a set. Any set consisting of all the things or elements related to a particular context is defined as a universal set. The difference of sets \(A\) and \(B\) is the set of elements that belongs to set \(A\) but not to set \(B.\). Therefore, \(A – B = \left\{{2,3,8} \right\}\)
A set is a well-defined collection of objects. All the objects in a set should have a common feature or property, and it should be possible to infer whether any given object belongs to the set or not.
Let us understand sets through some examples.
Sets are of the following types:
A set that contains only one element is called a Singleton Set.
Example: \(A = \){\(x:x\) is neither prime nor composite natural number}
A set that does not contain any element is called an Empty set, or a Null set, or a Void set. An empty set is denoted by the symbol \(\varphi \) or \(\{ \,\} .\)
Example:\(P = \){ \(x:x\) is a leap year between \(2017\) and \(2019\)}
Consider the following sets:
\(A = \) {the students of your school}
\(L = \left\{{P,Q,R,S} \right\}\)
In set \(A\) the number of elements is the number of students in your school. And, in set \(L,\) the number of elements is \(4.\) Since it is possible to count the number of elements in both sets \(A\) and \(L,\) i.e. they contain finite elements, such sets are called finite sets.
Consider the following sets:
\(B = \){\(x:x\) is an even number}
\(J = \) {\(x:x\) is a multiple of \(7\)}
Since set \(B\) contains all the even numbers that cannot be counted, the number of elements of this set is not finite.
Similarly, all the elements of \(J\) cannot be listed. We observed that the number of elements in \(B\) and \(J\) is infinite. Hence, such sets are called infinite sets.
Consider the following sets:
\(A = \) {Sachin,Dravid,Kohli}
\(B = \) {Dravid,Sachin,Dhoni}
\(C = \) {Kohli,Dravid,Sachin}
All the names that are in set \(A\) are in set \(C\) but not in set \(B.\) Thus, \(A\) and \(C\) have the same elements, but some elements of \(A\) and \(B\) are different. So, sets \(A\) and \(C\) are equal sets but sets \(A\) and \(B\) are not equal.
Two sets \(A\) and \(C\) are equal if every element in \(A\) belongs to \(C\) and every element in \(C\) belongs to \(A.\) Two equal sets, \(A\) and \(C,\) are represented as \(A = C.\)
The basic operations on sets are:
Let \(A\) and \(B\) be any two sets. The union of \(A\) and \(B\) is a set that consists of all elements of \(A\) and \(B.\) the common elements being taken only once. The symbol \(U\) is used to denote the union. Symbolically, the union is represented as \(A \cup B.\) and usually read as \(A\) union \(B.\)
Example: Let \(A = \left\{{2,4,6,8} \right\}\) and \(B = \left\{{6,8,10,12} \right\}.\) Find \(A \cup B\)
We have \(A \cup B = \left\{{2,4,6,8,10,12} \right\}\) \(6\) and \(8\) are the common elements that have been taken only once while writing \(A \cup B.\)
The intersection of sets \(A\) and \(B\) is the set of all elements which are common to both \(A\) and \(B.\)
The symbol \( \cap \) is used to denote the intersection. The intersection of sets \(A\) and \(B\) is the set of all those elements which belong to both \(A\) and \(B.\) Symbolically, the intersection is represented as \(A \cap B = \) {\(x:x \in A\) in and \(x:x \in B.\)}
Example: Let \(A = \left\{{2,4,6,8} \right\}\) and \(B = \left\{{6,8,10,12} \right\}.\) Find \(A \cap B.\)
Here, \(6\) and \(8\) are the only common elements that are common to both \(A\) and \(B.\). Hence \(A \cap B = \left\{{6,8} \right\}.\)
The complement of sets is the set of all elements in the given universal set that are not in \(A.\) It is represented as \(A’.\)
Example: Let \(U = \left\{{1,2,3,4,5,6,7,8,9,10} \right\}\) and \(A = \left\{{1,2,4,5} \right\}.\) Find \(A’.\) In the above example, it can be observed that \(3,6,7,8,9,10\) are the elements of \(U\) which do not belong to set \(A.\) So, \(A’ = \left\{{3,6,7,8,9,10} \right\}.\)
In the below picture, \(B\) and \(C\) are two sets such that \(B \cap C = \phi ,\) then \(B\) and \(C\) are called disjoint sets.
Example: let \(A = \left\{{2,4,6,8} \right\}\) and \(B = \left\{{1,3,5,7} \right\}.\) Then, \(A\) and \(B\) are disjoint sets because there are no common elements in sets \(A\) and \(B.\)
The difference of sets \(A\) and \(B\) is the set of elements that belongs to \(A\) but not to \(B.\) Symbolically, the difference of sets is represented as \(A – B.D\)
We denote the difference of \(A\) and \(B\) by \(A – B\) or simply \(A\) minus \(B\) and the difference of \(B\) and \(A\) by \(B – A\) or simply \(B\) minus \(A.\)
So, \(A – B = \) {\(x:x \in A\) and \(x \in B\)} and \(B – A = \){\(x:x \in B\) and \(x \in A\)}
Examples: Let \(A = \left\{{2,3,4,6,8} \right\}\) and \(B = \left\{{6,4,5,11,14} \right\}.\) Find \(A – B.\)
The difference of sets \(A\) and \(B\) is the set of elements that belongs to set \(A\) but not to set \(B.\). Therefore, \(A – B = \left\{{2,3,8} \right\}\)
Readers can check Difference of Sets Example and practise problems below.
Q.1. \(A = \left\{{2,4,7,9,11,12} \right\}\) and \(B = \left\{{1,2,3,4,5} \right\}.\) Find \(A – B\) and \(B – A.\)
Ans: We can say that \(A – B = \left\{{7,9,11,12} \right\}\) as these elements belong to \(A\) but not to \(B.\) And, \(B – A = \left\{{1,3,5} \right\}\) as these elements belong to \(B\) but not to \(A.\)
Q.2. \(A = \left\{{a,b,c,d,e,f,g,h} \right\}\) and \(B = \left\{{a,e,f,g,h,i,j} \right\}.\) Find \(A – B\) and \(B – A.\)
Ans: The unique elements in \(A\) are \(b,c,d,\) and the unique elements in \(B\) are \(I\) and \(j.\)
Thus, \(A – B = \left\{{b,c,d} \right\}\) and \(B – A = \left\{{i,j} \right\}\)
Q.3. If \(A = \left\{{1,2,6,8,9} \right\}\) and \(A \cap B = \left({1,8} \right).\) Find \(A – B.\)
Ans: The intersection of \(A\) and \(B,\) \(\left({A \cap B} \right)\) is the set of all elements common in both \(A\) and \(B.\)
Therefore, \(\left({A – B} \right) = A – \left({A \cap B} \right)\)
\( \Rightarrow \left({A – B} \right) = \left\{{2,6,9} \right\}\)
Therefore, \( \Rightarrow \left({A – B} \right) = \left\{{2,6,9} \right\}\)
Q.4. \(M = \left\{{a,e,i,o,u} \right\}\) and \(N = \left\{{a,e,k,u} \right\}.\) Find \(M – N.\)
Ans: The elements in only \(M\) are \(i,o.\)
Therefore, \(\left({M – N} \right) = \left\{{i,o} \right\}.\)
Q.5. \(X = \left({a,b,c,d,e} \right)\) and \(Y = \left({f,b,d,g} \right).\) Find \(X – Y.\)
Ans: The intersection of \(X\) and \(Y\) \(\left({X \cap Y} \right)\) is the set of all elements common in both \(X\) and \(Y.\)
Therefore, \(\left({X – Y} \right) = X – \left({X \cap Y} \right).\)
\( \Rightarrow \left({X – Y} \right) = \left\{{a,b,c,d,e} \right\} – \left\{{b,d}\right\}\)
\( \Rightarrow \left({X – Y} \right) = \left\{{a,c,e} \right\}\)
Therefore, \(\left({X – Y} \right) = \left\{{a,c,e} \right\}.\)
Q.6. Given the sets \(X = \left\{{a,b,c,d,e,f,g,h} \right\}\) and \(Y = \left\{{f,b,d,g,h} \right\}.\) Find the value of the set \(X – Y.\)
Ans: The intersection of \(X\) and \(Y,\) \(\left({X \cap Y} \right)\) is the set of all elements common in both \(X\) and \({Y.}\)
Therefore, \(\left({X – Y} \right) = X – \left({X \cap Y} \right).\)
\( \Rightarrow \left({X – Y} \right) = \left\{{a,b,c,d,em,f,g,h} \right\} – \left\{{b,d,f,g,h} \right\}\)
\( \Rightarrow \left({X – Y} \right) = \left\{ {a,c,e} \right\}\)
Therefore, \(\Rightarrow \left({X – Y} \right) = \left\{{a,c,e} \right\}.\)
The Difference of Sets \(A\) and \(B\) in this order is the set of elements that belongs to set \(A\) but not to set \(B.\) We denote the difference of \(A\) and \(B\) by \(A – B\) or simply \(A\) Minus \(B.\) And the difference of \(B\) and \(A\) by \(B – A\) or simply \(B\) minus \(A.\) The properties of sets are union, intersection, complement, and difference.
Q.1. How do you find the Difference of a Set?
Ans: To find the difference of sets \(A\& B,\) we begin by writing all the elements of A and then remove the elements of \(A\) that is also an element of \(B.\)
Q.2. What are the types of Sets?
Ans: There are different types of Sets are,
1. Empty Set
2. Singleton Set
3. Finite Set
4. Infinite Set
5. Equal Set
6. Universal Set
7. Subset
Q.3. Explain the Difference of Sets with example?
Ans: The difference of sets \(A\) and \(B\) in this order is the set of elements that belongs to \(A\) but not to \(B.\)
Examples: Let \(A = \left\{{1,2,3,4,5,6,8} \right\}\) and \(B = \left\{{3,4,5,12,14} \right\}.\) Find \(A – B.\)
So, here the set of elements that belongs to set \(A\) but not to set \(B.\)
Therefore, \(A – B = \left\{{1,2,6,8} \right\}\)
Q.4. What does ∩ mean in sets?
Ans: The symbol \( \cap \) is used to denote the intersection. The intersection of sets, \(A\) and \(B\) is the set of all those elements that belong to \(A\) and \(B,\) represented as \(A \cap B.\)
Q.5. What is \(A\) minus \(B\) in sets?
Ans: \(A\) minus \(B\) in sets means the set of elements that belongs to \(A\) but not to \(B.\)
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