NCERT Solutions for Linear Equations in One Variable Exercise 2.3 Class 8 Maths

NCERT Solutions for Class 8 Maths Exercise 2.3: NCERT Solutions for Class 8 Maths Linear Equations in One Variable Ex 2.3 provided here on this page. The NCERT Solutions provided here will help students with their studies. NCERT textbooks are recommended by CBSE for students in grades 1 through 12. As a result, it’s very important to go through all of the NECRT textbook’s exercise questions multiple times. However, some of the NCERT exercises’ questions are difficult to answer and necessitate analytical skills. This is where our NCERT solutions come in handy.

We have a dedicated team of experts who have excellent knowledge and understanding of all the concepts discussed in Class 8 Maths. They have curated the solutions after intensive research to make sure that the solutions are error-and comply with CBSE standards. NCERT Solutions will help students not only in answering questions in the final exam but also in understanding the various topics discussed in the classroom in more detail. To help students access these solutions offline, we have provided the solutions in PDF format. Read till the end to know more.

NCERT Solutions for Ex 2.3 Class 8 Maths: Overview

NCERT Solutions are one of the greatest resources for students who have questions about the topics covered in the chapter. Students can pass their exams with flying colours if they use these strategies. Let’s take a look at the overview, before we provide you with the solutions:

NCERT Solutions for Class 8 Maths Ex 2.3 Download PDF

We have provided the complete NCERT Solutions here on this page. Students can view the solutions and copy and paste that. However, viewing the solutions requires a proper internet connection. Hence, we have also provided the full solutions in PDF format. Students can download the PDF solutions with one click and save them on their devices. To download the solutions, simply click on the link provided below:

NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3 PDF – Download Here

Here we have provided the complete solutions for Class 8 Maths Ex 2.3. You can view these solutions and refer to these answers.

1. Solve the following equations and check your results.

(i) Solve 3x = 2x+18
Solution: Given: 3x = 2x+18
Transposing 2x to LHS, we get,
3x-2x = 18
⇒ x =18
Verification: Substituting x=18 on LHS and RHS
LHS: 3x = 3×18 = 54
RHS: 2x+18 = 218+18 = 54 ∴ LHS=RHS
Hence, verified.

(ii) 3m = 5m-8/5
Solution: Given, 3m = 5m-8/5
Transposing 3m to RHS
⇒ 0 = 5m – 3m – 8/5
⇒ 0 = 2m – 8/5
Adding 8/5 on both sides
⇒ 8/5 = 2m-8/5+8/5
⇒ 8/5 = 2m
⇒ 2m = 8/5
Dividing both sides by 2
⇒ m = 8/10
⇒ m = 4/5
Verification: Substituting m = 4/5 on LHS and RHS
LHS: 3m
= 3*4/5
= 12/5
RHS: 5m – 8/5
= 5*4/5 – 8/5
= 12/5
LHS = RHS
Hence, verified.

(iii) 5t-3=3t-5
Solution: Given 5t-3 = 3t-5
Transposing 3t to LHS, we get,
5t-3-3t = -5
⇒ 5t-3t-3 = -5
⇒ 2t-3= -5
Transposing 3 to RHS, we get,
⇒ 2t=-5+3
⇒ 2t=-2
Divide by 2 on both sides,
⇒ 2t2 = -22
⇒ t=-1
Verification: Substituting t=-1 on LHS and RHS
LHS: 5t-3
=5-1-3 =-8
RHS: 3t-5 =3-1-5 =-8
LHS = RHS
Hence, verified.

(iv) 5x+9=5+3x
Solution: Given 5x+9=5+3x
Transposing 3x to LHS, we get,
⇒ 5x-3x+9=5
⇒ 2x+9=5
Transposing 9 to RHS,
⇒ 2x = 5-9
⇒ 2x = -4
Dividing both sides by 2,
⇒ x = -42
⇒ x = -2
Verification: Substituting x=-2 on LHS and RHS
LHS: 5x+9
=5-2+1 =-1
RHS: 5+3x =5+3-2 =-1
LHS = RHS
Hence, verified.

(v) 4z+3=6+2z
Solution: Given 4z+3=6+2z
Transposing 2z to LHS
⇒ 4z-2z+3 = 6
⇒ 2z+3 = 6
Transposing 3 to RHS
⇒ 2z = 6-3
⇒ 2z = 3
Dividing both sides by 2
⇒ z = 3/2
Verification: Substituting z=3/2 on LHS and RHS
LHS: 4z+3
=4*3/2+3
=6+3=9
RHS: 6+2z
=6+2*3/2
=6+3=9
LHS=RHS
Hence, verified.

(vi) 2x-1=14-x
Solution: Given 2x-1=14-x
Adding x to both sides,
⇒ 2x+x-1 = 14-x+x
⇒ 3x-1=14
Adding 1 to both sides,
⇒ 3x-1+1=14+1
⇒ 3x=15
Dividing both sides by 3,
⇒ x = 15/3
⇒ x = 5
Verification: Substituting x=5 on LHS and RHS
LHS: 2x-1
=2*5-1 = 9
RHS: 14-x =14-5 =9
LHS =RHS
Hence, verified.

(vii) 8x+4=3x-1+7
Solution: Given 8x+4 = 3x-1+7
⇒ 8x+4 = 3x-3+7
⇒ 8x+4 = 3x+4
Transposing 3x to LHS,
⇒ 8x-3x+4 = 4
⇒ 5x+4 = 4
Transposing 4 to RHS,
⇒ 5x = 4-4
⇒ 5x = 0
⇒ x = 0
Verification: Substituting x=0 on LHS and RHS,
LHS: 8x+4
=8*0+4
=4
RHS: 3x-1+7
=3*0-1+7
=-3+7
=4
LHS=RHS
Hence, verified.

(viii) x=45x+10
Solution: Given x=45x+10.
Multiplying both sides by 5
⇒ 5x=5×45x+10
⇒ 5x=4x+10
⇒ 5x=4x+40
Transposing 4x to LHS
⇒ 5x-4x=40
⇒ x=40
Verification: Substituting x=40 on LHS and RHS
LHS: x=40
RHS: 45x+10
= 45*40+10
= 4550
= 40
LHS=RHS
Hence, verified.

(ix) 2×3+1=7×15+3
Solution: Given 2×3+1=7×15+3
Multiply both sides by 15
⇒ 15×2×3+15 = 15×7×15+3×15
⇒ 10x+15=7x+45
Transposing 7x to LHS
⇒ 10x-7x+15=45
⇒ 3x+15=45
Subtract 15 from both sides
⇒ 3x+15-15=45-15
⇒ 3x=30
Divide by 3 on both sides
⇒ 3×3=30/3
⇒x=10
Verification: Substituting x=10 on LHS and RHS
LHS: 2×3+1
=2*10*3+1
=233
RHS: 7×15+3
=7*10*15+3
=143+3
=233
LHS=RHS
Hence, verified.

(x) 2y+53=263-y
Solution: Given, 2y+53=263-y
Adding y to both sides,
⇒ 2y+y+53 = 263-y+y
⇒ 3y+53 = 263
Multiplying both sides by 3,
⇒ 3×3y+5 = 26
⇒ 9y+5=26
Transposing 5 to RHS,
⇒ 9y = 26-5
⇒ 9y = 21
Dividing both sides by 9,
⇒ y = 219
⇒ y = 73
Verification: Substituting y=73 on LHS and RHS,
LHS: 2y+53
=273+53
=193
RHS: 263-y
=263-73
=193
LHS=RHS Hence, verified.

Benefits of NCERT Solutions for Class 8 Maths Exercise 2.3

Using NCERT solutions to write answers in Class 8 final examinations has a number of advantages. These solutions will be helpful for all those students who study under a board that follows the NCERT curriculum since they cover the whole CBSE Class 8 syllabus. The NCERT solutions provided here will also help students understand the important concepts of Class 8 Maths in an easy way. Some of the benefits of referring to Embibe’s NCERT solutions are as follows:

1. To ensure that all the solutions are accurate and error-free, our team of academic experts has properly researched and proofread them.
2. All solutions have detailed step-by-step explanations for improved learning of students.
3. The solutions are written in a very easy-to-understand language so that all types of students can understand and learn from them.
4. We have provided exercise-wise NCERT solutions for various exercises available in a chapter.
5. The solutions are supported by proper illustrations, images and graphs for a better and faster understanding.
6. We have provided NCERT chapter-by-chapter solutions in PDF format so that they are easily accessible.
7. The entire syllabus for Class 8 Maths is covered in NCERT solutions.

About NCERT Solutions for Class 8 Maths Ex. 2.3

Here we have provided the important notes on Class 8 Maths Chapter 2. All the important topics discussed in this chapter are summarised below:

Algebraic Equation: An algebraic equation is an equation involving constants and variables. It has an equality sign that separates left-hand values from right-hand values. The expression to the left of the equality sign is called the left side and the expression to the right of the equality sign is called the right side. In an equation, for some specific values ​​of the variables, the values ​​of the expressions on the left side and the right side are equal. These values ​​of the variables are called solutions of that equation.

The exponents of the variables in an equation are necessarily non-negative integers. An equation in which the expression forming the equation has only one variable and the maximum exponent of that variable in the equation is 1, is called a linear equation with one variable. In a linear equation, both sides of the equality sign can have linear expressions. To solve an equation, we perform the same mathematical operation on both sides of that equation, so that the balance between the left side and the right side is not disturbed. In an equation, terms can be transferred from one side of the equation to the other.

FAQs on NCERT Solutions for Linear Equations in One Variable

Here are some of the frequently asked questions on CBSE Class 8 Maths Ex. 2.3:

Q.1: Is CBSE Class 8 Maths Chapter 2 – Linear Equation in One Variable difficult to understand?
Ans: The chapter is not difficult to understand. All the concepts are explained elaborately in NCERT textbooks. We have provided complete NCERT solutions here on this page to help students learn the concepts even better.

Q.2: How many questions are there in Ex. 2.3 of Class 8 Maths?
Ans: There is a total of 1 question in Ex. 2.3 of Class 8 Maths Chapter 2.

Q.3: Which is the best book for NCERT Solutions for Class 8 Maths?
Ans: You can find all the solutions for Class 8 Maths on Embibe for. We have Embibe Big Books where we have provided the solutions not only for NCERT textbook exercises but also for other well-known books available in the market.

Q.4: How are NCERT Solutions helpful in solving Class 8 Maths Exercise 2.3?
Ans: NCERT Solutions will not only help students in answering questions in the final exam but also in clearing their doubts or queries regarding the topic discussed.

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