NCERT Solutions for Mensuration Exercise 11.1 Class 8 Maths

NCERT Exercise 11.1 Class 8 Maths Solutions: NCERT solutions for Class 8 Maths chapter 11 exercise 11.1 teaches students about ‘Mensuration’. Students must practice NCERT exercise 11.1 Class 8 Maths solutions to have a clear picture of the chapter and be thorough with the complex concepts. Subject experts provide these NCERT solutions at Embibe to help students score more in the exams and clear their doubts.

Class 8 Maths chapter 11 exercise 11.1 will teach students about various interesting concepts of mensuration. Students will learn to solve the questions in a time-bound manner to score higher marks in the exam. The main goal of Embibe is to help students master the mathematical skills to kick-start their educational journey. We will provide all the NCERT solutions for Class 8 Maths exercise 11.1 to help students with their exam preparations. Read on to learn more.

NCERT Exercise 11.1 Class 8 Maths Solutions: Overview

The NCERT solutions for exercise 11.1 Class 8 Maths ‘Mensuration’ are a series of questions and answers for most of the textbook problems. Subject experts have created all solutions based on the most recent CBSE syllabus and norms. The primary goal is to provide students with access to high-quality NCERT solutions and a head starts on their studies. Our mission is to help kids achieve their full potential by providing additional skill-building activities targeted to their grade levels, abilities, and interests.

Before we jump into further details, let us have an overview of NCERT solutions for ex 11.1 Class 8 Maths:

NCERT Exercise 11.1 Class 8 Maths Solutions: PDF

In NCERT solutions for Class 8 Maths chapter 11 exercise 11.1, students will learn about the measurement of geometric figures and their parameters like length, volume, shape, surface area, lateral surface area, etc. In the other half of the chapter, solid shapes like the cube, cuboid, and cylinder are discussed along with diagrams. The important mensuration formulas and properties of different geometric shapes and figures are also covered in this chapter.

This chapter is based on formulas and thus, requires knowledge of the concepts and application of the formulas. Students will learn to use the formulas in the right way after going through the in-text exercise questions, along with their solutions. They will also learn time management skills to improve their way of solving a given question. Download the NCERT solutions for Maths Class 8 ex 11.1 from the PDF link below to study offline:

Q.1. A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?

Solution: Given, side of square =60 m and length of rectangle =80 m
We know that, perimeter of square =4×(side).
Perimeter of rectangle =2(l+b) ,where l=length, b=breadth. Perimeter of square =4×60=240 m Perimeter of rectangle = 2l+b
=2(80+b) Given, Perimeter of square = Perimeter of rectangle ⇒240=2(80+b) ⇒b=40 m
We know that, area of square =(side)2
Area of rectangle =l×b
Area of Square =60×60=3600 m2 Area of rectangle = 80×40=3200 m2 Therefore, area of square is greater than
area of rectangle. Hence, the required answer is a.

Q.2. Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹55 per m2. [ write only numerical value without rupee symbol]

Solution:

Given, side of square =25 m
Length of house =15 m Breadth of house =20 m We know that area of square =a2 Area of rectangle =l×b Area
of remaining portion = Area of square plot – Area of house Now, area of Square = 25×25=625 m2 Area of
house =15×20=300 m2
Hence, area of remaining portion =625 m2-300 m2=325 m2
Total cost =₹325×55=₹17,875.
Hence, the total cost for developing a garden is ₹17,875.

Q.3. The shape of a garden is rectangular in the middle and semicircular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20-3.5+3.5 meters].

Solution:

Given total length =20 m\
Diameter of the semicircle =7 m ⇒ Radius of the semicircle =72 m=3.5 m Length of rectangular field
=20-(3.5+3.5) m =20-7 m=13 m Breadth of the rectangular field =7 m Area of rectangular field
=l×b =13×7 m2=91 m2 Area of two semi-circles =2×12×π×r2 =2×12×227×3.5×3.5 m2 =38.5 m2
Therefore, area of the garden =91+38.5 m2=129.5 m2
Perimeter of two semi circular arcs=2×πr
=2×227×3.5 m =22 m Hence, Perimeter of garden =22+13+13 m =48 m

Q.4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2 ? (If required you can split the tiles in whatever way you want to fill up the corners).

Solution:

Given, base of the flooring tile of a parallelogram shape=24 cm
Height =10 cm.
Area of a parallelogram =base×height Area of one tile =24 cm×10 cm=240 cm2 We know that 1 m=100 cm
Area of the floor (Total area) = 1080 m2=1080×10000=10800000 cm2.
Hence,
Total tiles required =Total areaArea of one tile
=1080×10000240
=45000 tiles
Therefore, 45000 tiles are required to cover area of 1080 m2

DOWNLOAD NCERT EXERCISE 11.1 CLASS 8 MATHS SOLUTIONS

About NCERT Exercise 11.1 Class 8 Maths Solutions

NCERT solutions for Class 8 Maths chapter 11 exercise 11.1 are designed to assist students in understanding the concepts from previous classes. Rectangles, triangles, and circles all have areas and perimeters that may be calculated. Students may be asked to compare the areas of two shapes, calculate the cost of fencing a rectangular figure, or answer problems based on a combinatorial configuration in these word problems. NCERT solutions for exercise 11.1 Class 8 Maths covers a total of five moderate level questions.

When answering these questions, keep in mind that you must be familiar with the formulas for such shapes. Students must have a good basic knowledge of these figures before moving on to the higher-order questions presented in this exercise. The important formulas used in mensuration are mentioned below:

• Area of a rectangle = a × b, b is the breadth and a is the length. By multiplying these two dimensions students can solve the area of a rectangle.
• Area of a square = a × a, a is the length of each side. As all the four sides are of equal length, its square.
• Area of a triangle = 1/2 * b * h, b is the base and h is the height. Students will use the Heron’s formula and the Pythagoras theorem to find the solution.
• Area of a parallelogram = b × h, b is the base and h is the corresponding perpendicular.
• Area of a circle = πr 2, π is a constant given by 22/7 or 3.14 and r is the radius of the circle.

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NCERT Exercise 11.1 Class 8 Maths Solutions: Chapter Summary

To introduce students to more plane figures and three-dimensional solids, NCERT solutions for mensuration build on ideas of the area and perimeter of figures such as triangles, rectangles, and others they studied in earlier classes. This chapter effectively integrates several concepts, allowing students to apply them to real-world situations. Additionally, it includes the problems of volume and capacity. A 3D solid shape’s volume is the amount of space it takes up, whereas a container’s capacity is the amount of liquid it can hold. Chapter 11 of the NCERT solutions for Class 8 Maths focuses on cubes, cuboids, and cylinders.

Students must remember to use the same units when working with the perimeter, area, surface area, and volume. Various exercises are also included in the NCERT solutions for Class 8 Maths to demonstrate this concept. The questions were chosen by mathematical geniuses to provide a complete learning experience for children. They cover all elements in this chapter that fall under a specific topic. Students are also taught how to use visualisation to their advantage. For example, if students are asked to find the surface area of a cube, they must mentally visualise the shape and comprehend its components to answer problems based on it. This is one of the most important skills a child can learn.

Benefits of NCERT Exercise 11.1 Class 8 Maths Solutions

Some of the benefits of NCERT Class 8 Maths chapter 11 exercise 11.1 solutions are mentioned below:

1. The NCERT solutions are offered step-by-step to help students understand how to answer questions on the exam.
2. The examination is based on the NCERT textbooks. To do well on the final exams, students must carefully go over the in-text exercises.
3. Students develop complex problem-solving skills when studying from the NCERT textbooks. This helps them in obtaining excellent exam results.
4. Students develop time management skills in preparation for exams because practising allows them to answer any question in a timely manner.
5. The NCERT solutions assist students in comprehending the types of questions that will be asked throughout the exam. As a result, they can get good results on their final exams.
6. NCERT solutions are the most trustworthy study materials because they follow CBSE guidelines, allowing students to do well in their exams.
7. After completing the in-text exercises and carefully working on them to avoid any tiny errors, students can quickly identify areas for development.
8. NCERT textbooks are the finest for students. They must solve them to improve their grades, as no other reference book compares to the NCERT textbook.

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FAQs on NCERT Exercise 11.1 Class 8 Maths Solutions

Some of the frequently asked questions on NCERT exercise 11.1 Class 8 Maths solutions are mentioned below:

Q.1: How to master chapter 11 of Class 8 Maths?
Ans: Students must practice and be diligent in order to become a master of any subject. Furthermore, this chapter contains various formulas that can be difficult to remember. To address this problem, students should visit the above-mentioned links on a regular basis so that they may recall concepts in seconds when needed, especially during an examination.

Q.2: What important topics are covered in NCERT exercise 11.1 Class 8 Maths?
Ans: Finding the area and perimeter of a square, rectangle, triangle, polygon, trapezium, circle, and a general quadrilateral, as well as determining the surface area (total, lateral, or curved) of cubes, cuboids, and cylinders, as well as their volumes, are all topics covered in NCERT solutions for exercise 11.1 Class 8 Maths.

Q.3: How many questions are there in chapter 11 of Class 8 Maths?
Ans: In Class 8 Math chapter 11, there are a total of 34 well-researched problems. Seven of the problems are simple formula-based sums, 10 are slightly more difficult, and 17 need a student to use reasoning skills to complete.

Q.4: Where can I download the NCERT solutions for exercise 11.1 Class 8 Maths?
Ans: Students can download the NCERT solutions for exercise 11.1 Class 8 Maths on Embibe and for.

Q.5: List the important formulas used in mensuration.
Ans: The important formulas used in chapter 11 mensuration are listed below:
1. Area of a trapezium = half of the sum of the lengths of parallel sides × perpendicular distance between them
2. Area of a rhombus = half the product of its diagonals
3. TSA (total surface area) of a cuboid = 2(lb + bh + hl)
4. Volume of a cuboid = l × b × h

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