NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths

Exercise 4.3 Class 7 Maths: NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths are available to guide the students in thoroughly contemplating all of the solutions in the exercises to achieve high grades. The NCERT Solutions for Class 7 Maths incorporate all solutions with supplementary information to spice up the students’ learning experience with visual illustrations and solutions step-by-step.

Subject area specialists generate and analyse NCERT solutions following CBSE norms and the recently revised syllabus. The solutions are listed per chapter for easy reference. Students can use them at any time to study for their first and second semester exams and other competitive tests. Embibe has the PDF for the Simple Equation Exercise and the downloading links. Read the complete article to To learn more on Exercise 4.3 Class 7 Maths.

NCERT Solutions for Exercise 4.3 Class 7 Maths: Overview

Simple Equation Exercise 4.3 Class 7 Maths NCERT Solutions follow the latest CBSE rules and syllabus for 2024-25. Students can keep the PDFs of the exercises for later use. Before we get into the specific solutions for NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths, let’s go over some essential information.

Take a look at the following table:

Class 7 Maths Chapter 4 NCERT Solutions: PDF

All Simple Equation Exercise questions are answered in NCERT Solutions for Class 7 Maths Chapter 4 Simple equation. NCERT Solutions primarily assist students in identifying their strengths and shortcomings while also allowing for skill development. It enhances their self-confidence and performance on the second-term exam. Class 7 Maths Chapter 4 is included in the second semester CBSE Syllabus for 2022-23.

NCERT Solutions Class 7 provides students with step-by-step instructions to help them swiftly answer questions on the final exam. The answers are available for students to download in PDF format. Students can download and study the solutions for to score well on their final test. The questions and their step-by-step responses are as follows:

Q.1. Find the value of y for the equation: 2y+52=372

8

Solution: Given, 2y+52=372

⇒2y=372-52 (Transposing 52 to R.H.S.)

⇒2y=37-52

⇒2y=322 ⇒2y=16

On dividing both sides by 2, we get,

⇒y=162=8

Hence, the required answer is 8.

Q.2. Find the value of 10t for the equation 5t+28=10

-36

Solution: Given, 5t+28=10

⇒5t=10-28 (Transposing 28 to R.H.S.)

⇒5t=-18

On dividing both sides by 5, we get,

⇒t=-185

∴10t=-185×10=-36 Hence, the required answer is -36.

Q.3. What is the value of a in the equation a5+3=2.

-5

Solution: Given, a5+3=2

Transposing 3 to R.H.S., we get,

⇒a5=2-3 ⇒a5=-1

On multiplying both sides by 5, we get,

⇒a5×5=-1×5

⇒a=-5 Hence, the required answer is -5.

Q.4. Solve the equation and find the value of q: q4+7=5

-8

Solution: Given, q4+7=5

⇒q4=5-7 (Transposing 7 to R.H.S.)

⇒q4=-2

On multiplying both sides by 4, we get,

⇒q4×4=-2×4

⇒q=-8 Hence, the required answer is -8.

Q.5. Solve the following equation: 52x=-5.

-2

Solution: Given, 52x=-5

On multiplying both sides by 2, we get,

⇒5×2×2=-5×2 ⇒5x=-10

On dividing both sides by 5, we get,

⇒5×5=-105

⇒x=-2 Hence, the required answer is -2.

Q.6. Find the value of 2x for the equation 52x=254.

5

Solution: Given, 52x=254

On multiplying both sides by 2, we get,

⇒5×2×2=254×2 ⇒5x=252

On dividing both sides by 5, we get,

⇒5×5=252×15

⇒x=52 Therefore, the value of x is 52. Hence, the value of 2x is 52×2=5.

Q.7. Find the value of m in the equation: 7m+192=13.

12

Solution: Given, 7m+192=13

⇒7m=13-192 (Transposing 192 to R.H.S.)

⇒7m=26-192 ⇒7m=72

On dividing both sides by 7, we get,

⇒7m7=72×17

⇒m=12 Hence, the required answer is 12.

Q.8. Solve and find the value of z: 6z+10=-2.

-2

Solution: Given, 6z+10=-2

⇒6z=-2-10 (Transposing 10 to R.H.S.)

⇒6z=-12 On dividing both sides by 6, we get, ⇒6z6=-126 ⇒z=-2 Hence, the required answer is -2.

Q.9. Find the value of 9l for the equation 3l2=23

4

Solution: Given, 3l2=23

On multiplying both sides by 2, we get,

⇒3l2×2=23×2

⇒3l=43

On dividing both sides by 3, we get,

⇒3l3=43×13

⇒l=49

So, 9l=49×9=4 Hence, 9l=4.

Advantages of Solving Embibe’s NCERT Class 7 Maths Solutions

Students must solve the NCERT Class 7 chapters to understand the 10th board exam to score high marks in their Class 7 pre-board exam 2023-24. After conducting extensive research on the chapter, subject-matter experts prepare Class 7 Maths NCERT Solutions. Here are a few benefits of completing NCERT Class 7 Maths Solutions.

• NCERT Class 7 Maths Solutions 2023-24 is developed by Embibe’s subject matter experts and follows CBSE guidelines.
• Students receive thoroughly explained chapters and include step-by-step solutions to all questions.
• Students get a thorough assessment of ideas and important questions to understand the chapters completely.
• It consists of the marks and weighting for each question, which may be helpful for last-minute review and preparation.
• NCERT solutions can help students prepare for upcoming admission exams and do well on their Class 7 final test.
• Get PDFs of NCERT Class 7 Maths Solutions and in-text solutions to help you prepare for the exam.
• Students receive chapter-by-chapter mock test questions to assist them in preparing for their tests after thoroughly analysing and comprehending the NCERT Class 7 Solutions PDF.

About Class 7 Maths Chapter 4 Simple Equation

Exercise 4.3 of chapter 4 of the NCERT Textbook has an explanation of the concepts and some exercises to assess your understanding of the concept. Simple Equation Chapter 4 of Maths for Class 7 has 22 exercises, and there are 22 questions in Exercise 4.3. Our subject experts have provided detailed and step-by-step solutions for all questions in the NCERT Solutions for Class 7 Exercise 4.3 Maths Chapter 4 – Simple Equation so that students can understand the concept.

Simple Equation 

A variable and an ‘equal to’ sign make up a simple equation in the simplest of terms. Therefore, a simple equation is a mathematical representation of two expressions on either side of an equal sign. 

It mainly consists of a variable, frequently accompanied by a numerical constant. To understand this concept easily, consider the following example. 

3x – 4 = 5. It is a class 7 simple equation. In this representation, the x refers to a variable. Every equation of this category aims to find the value of x. However, you can also use other letters from the English alphabet to write a variable. 

Furthermore, the value of 3x – 4 must equal 5. As a result, an introductory class 7 equation keeps the same value on both sides of the ‘=’ sign.

You can move any number or variable from one side of the equation to the other in this scenario. Keep in mind that the sign preceding the number changes as well. When a negative integer is shifted to the other side, it becomes a positive integer.

Returning to this equation, you can apply -4 to the other side: 3x = 5+4 = 9.

As a result, x = 9/3 = 3. As a result, the variable x has a value of 3.

FAQs on NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths

Here are a few most frequently asked questions answered on NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths below:

Q.1: Is it possible to get a copy of NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths?
Ans: You can definitely get the NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths for from Embibe’s website and app. They are available in PDF format, so they’re easy to download.

Q.2: What is the number of questions are there in NCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths?
Ans: There are 22 questions in the NCERT textbook for Class 7 Maths Chapter 4 Exercise 4.3. you can also find the answers to these problems in the NCERT Solutions Class 7 Maths Chapter 4 Exercise 4.3. Subject matter experts approach these issues in the most straightforward manner possible so that the students can comprehend all of the concepts and approaches rapidly.

Q.3: In mathematics, what is a simple equation?
Ans: A simple equation is a relationship between two terms on either side of an equal sign. In addition, simple equations use one or more of the four mathematical operations of addition, subtraction, multiplication, and division.

Q.4: What is the most common type of simple equation?
Ans: ax+by+c=0 is a general form. It is one of the many ways students may write linear functions. The slope-intercept form y=mx+b or the slope-point form are two others.

Q.5: What are the simple equation rules?
Ans: Here are some rules of a simple equation,
Rule 1: You can add the same amount to both sides of an equation.
Rule 2: You can deduct the same amount from both sides of an equation.
Rule 3: An equal amount can be used to multiply both sides of an equation.
Rule 4: A non-zero, equal quantity can be used to divide both sides of an equation.

Download the Class 7 Maths NCERT Solutions for other chapters from the table below:

You can also check,

Embibe gives out CBSE Study Material that covers the complete CBSE Class 7 syllabus for Maths. You can also solve Class 7 Maths practice questions for every chapter in the CBSE Class 7 syllabus for Maths, which will help you prepare for the engineering and medical entrance exam.

We hope this article aboutNCERT Solutions for Simple Equations Exercise 4.3 Class 7 Maths was helpful to you. If you have doubts or questions regarding NCERT Solutions for Simple Equations, Exercise 4.3 Class 7 Maths, leave them in the comment section below, and we will get back to you at the earliest.

Stay tuned to Embibe for the recent updates on the NCERT Maths Class 7 Solution!!