Written By
Livia Ferrao
Last Modified 11-10-2024
Physics Formulas for JEE Mains 2025: Check Details Here
Physics Formulas for JEE Mains: The JEE Main Session 1 will be held in January, 2025 and Session 2 will be conducted in April, 2025. Preparing for JEE Mains includes various aspects. Memorising formulas for Physics, Chemistry and Mathematics is crucial to scoring well. Candidates use formulas to solve numerous problems asked in the JEE Mains question paper. This article provides essential Physics formulas for JEE Mains to help candidates improve their preparation skills for the exam.
The National Testing Agency (NTA) will conduct JEE Main 2025 in two phases. Both papers 1 and 2 will be conducted online for 3 hours. Keep reading to get more information on JEE Main Physics Formulas.
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Physics Formulas for JEE Mains – Description
Candidates can refer to the below-mentioned information to know the topic-wise formulas covered in the JEE Main Physics subject.
Physics Formulas for JEE Mains: Vectors
Candidates can refer to the below information to know the formulas covered in Vectors:
Dot Product: AB=AB, where is the angle between the two vectors
The Resultant Vector is written as R=A+B or R=k=1nAk
The Resultant Vector in Cartesian Form is R=A2+B2+2AB, where is the angle between the two vectors.
If A=Axi+Ayj+Azk then the Direction Cosines are =Ax/A, =Ay/A and =Az/A
If A=Axi+Ayj+Azk and B=Bxi+Byj+Bzk then the Dot-Product is AB=AxBx+AyBy+AzBz
Cross Product: AB=AB n where n is a Unit Vector perpendicular to both A and B
If A=Axi+Ayj+Azk and B=Bxi+Byj+Bzk, then the Cross-Product is given by the Determinant
ij=k, jk=i and ki=j
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Physics Formulas for JEE Mains: Kinematics
Candidates can refer o the below pointers to know the formulas covered in Kinematics:
v=dr/dt and a=dv/dt and a=d2r/dt2
For 1-D Motion: a=v(dv/dx)
v=u+at, s=ut+(1/2)at2 and v2=u2+2as
sn-sn-1=u+(a/2)(2n-1)
v (relative)=v (actual)-v (reference)
Projectile Motion Initial Horizontal Velocity is ux=u
Projectile Motion Initial Vertical Motion is uy=u
Velocity at any instant of a Projectile Motion is v=u i+(u-gt) j
Horizontal Distance at any time is x=ut
Time of Flight is T=2u/g
Maximum Height of the Projectile is H=u22/2g
Horizontal Range is R=u22/g
Equation of Trajectory is y=x-gx2/( 2u22 )
Time of Flight for the Horizontal Projection from a cliff is T=2h/g
Horizontal Range for the Horizontal Projectile from a cliff is R=uT
Angle of velocity at any instant for Horizontal Projection from a cliff is =(gt/u)
Physics Formulas for JEE Mains: Laws of Motion and Friction
The following are the formulas covered in Laws of Motion and Friction:
Fundamental Forces of Nature are Gravitational Force, Electromagnetic Force, Weak Nuclear Force and Strong Nuclear Force.
F=dp/dt and F=ma is mass is constant
Impulse j=Ft in discrete case and j=t1t2F dt
Acceleration of Pulley when both masses are downwards is a=| m1-m2 |g/( m1+m2 )
Tension in the string of a Pulley System when masses are downwards is T=2m1m2g/( m1+m2 )
Man in a lift going upwards: Fnet=m(g+a)
Man in a lift going upwards: Fnet=m(g-a)
Centripetal Force is F=mv2/r=m2r
Static Frictional Force is f=sN where N is the Normal Force on the object
Kinetic Frictional Force is f=kN where N is the Normal Force on the object
Angle of Friction is = mg sin θ
Block sliding on an incline with angle of Repose : f=mg and N=mg
Physics Formulas for JEE Mains: Work Power and Energy
The following are the formulas covered in Work Power and Energy:
Work Done W=Fd when distance is non-variable and W=abFs when distance is variable
Kinetic Energy K=mv2/2
Potential Energy U=mgh+h where h is the height from the reference line
Conservative Force F= -U, in 1-D, it is F= -dU/dx
Work Energy Theorem: W (all forces)=K=Kf-Ki
Power P=Fv or P=W/t
Physics Formulas for JEE Mains: Circular Motion
Candidates can refer to the below information to know the formulas covered in Circular Motion:
Time Period T=1/f is reciprocal of Frequency
=l/r, =d/dt=2/T=2f and =d/dt
=v/r or v=r
Net acceleration a=r+v and a=( 2r )2+( r )2
Maximum velocity without skidding is v=Rg
Maximum velocity for banked road is v= (+1- )Rg
Bending of a Cyclist: vr*g*tan
Condition to complete the vertical circle is u5gR
Condition for Oscillation is u2gR and the Tension in the string is T=mg+mv2/R
Condition for leaving path is 2gR<u<5gR
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Physics Formulas for JEE Mains: Center of Mass
The following are the formulas covered in Center of Mass:
The Center of Mass along the x-axis is XCM=(1/M)i=1nmixi where M is the total mass
The Center of Mass along the y-axis is YCM=(1/M)i=1nmiyi where M is the total mass
The Center of Mass along the z-axis is ZCM=(1/M)i=1nmizi where M is the total mass
The Center of Mass for Continuous Distribution is RCM=(1/M)r dm
If the total mass is M and a small part of mass m is removed then the Center of Mass is given by XCM=(Mx-m)/(M-m), YCM=(My-m)/(M-m) and ZCM=(Mz-m)/(M-m)
The Center of Mass when the object is moving with some velocity is vCM=(1/M)i=1nmivi
The Center of Mass when the object is moving with some acceleration is aCM=(1/M)i=1nmiai
Coefficient of Restitution is e=(v2-v1)(u1-u2)
Law of Conservation of Linear Momentum: i=1nmiui=j=1nmjvj
Loss of Kinetic Energy in inelastic collision is K=(1/2M)[ m1m2(1-e2)(u1-u2)2 ]
Law of Conservation of Linear Momentum for Oblique Collision is i=1nmiui=j=1nmjvj
Thrust Force on a Rocket is vr(-dm/dt)
Velocity of a Rocket at any time is v=u-gt+v1(m0/m)
Physics Formulas for JEE Mains: Rotational Motion
Candidates can refer to the below information to know the formulas covered in Rotational Motion:
Angular Momentum L=rp=I where I is the Moment of Inertia
Torque =rF=dL/dt
Rotational Kinetic Energy K=I2/2=L2/2I
Rotational Power P=
Equations of Motion are =0+t, =0t+t2/2 and 2=02+2
The nth angular displacement is n-n-1=0+(2n-1)/2
Moment of Inertia I=i=1nmiri2 in discrete case and I=r2 dm
Radius of Gyration is k=I/M
Parallel Axis Theorem Iaxis=ICM+Md2
Perpendicular Axis Theorem Iz=Ix+Iy
Moment of Inertia of some common objects –
Rod of mass M and length L along its center I=ML2/12
Rod of mass M and length L along its corner I=ML2/3
Rectangular Lamina of mass M, length L and width W along its width I=ML2/12
Rectangular Lamina of mass M, length L and width W along its length I=MW2/12
Rectangular Lamina of mass M, length L and width W along its center I=M(L2+W2)/12
Ring of radius R along a normal to the plane passing through the center I=MR2
Disc of radius R along a normal to the plane passing through the center I=MR2/2
Circular Hollow Disc of inner radius r and outer radius R along a normal to the plane passing through the center I=M(r2+R2)/2
Hollow Cylinder of radius R along its length passing through the center I=MR2
Hollow Cylinder of length L and radius R along the normal to its length and passing through the center I=M(L2+6R2)/12
Solid Cylinder of radius R along its length I=MR2/2
Solid Cylinder of length L and radius R along the normal to its length and passing through the center I=M(L2+3R2)/12
Hollow Sphere of radius R along its center I=2MR2/3
Solid Sphere of radius R along its center I=2MR2/5
Total Kinetic Energy of Rolling Motion is K=[ mvCM2+I2 ]/2
Total Angular Momentum of Rolling Motion is L=mvCMR+I
Pure Rolling without slipping on stationary surface –
vCM=R and aCM=R
Forward Slipping happens when vCm>R
Backward Slipping happens when vCM<R
Total Kinetic Energy is K=(1/2)mvCM( 1+k2/R2 )
Formulas for Pure Rolling Motion in Inclined Plane with mass M, radius R and inclination –
Acceleration a=gR2/( k2+R2 )
Minimum Frictional Coefficient =k2/(k2+R2)
Work Done by Torque is W=d
Physics Formulas for JEE Mains: Gravitation
The following are the formulas covered in Gravitation:
Newton’s Law of Gravitation is F=Gm1m2/R2 where G6.67*10-11Nm2/kg2
Gravitational Field is GM/R2
Gravitational Field outside a Spherical Shell is -GM/r2 where r>R
Gravitational Field on the Surface of the Spherical Shell is -GM/R2
Gravitational Field inside the Spherical Shell is 0
Gravitational Field outside a Solid Sphere is -GM/r2 where r>R
Gravitational Field inside a Solid Sphere is -GMr/R3 where r<R
Acceleration due to gravity is g=GM/R2
Acceleration due to gravity at height h above the surface is gh=g(1-2h/R) when h<<<R
Acceleration due to gravity at depth d from the surface is gd=g(1-d/R)
Acceleration due to gravity at latitude is g=g-2R2
Gravitational Potential due to a point mass is V= -GM/r
Gravitational Potential inside a Spherical Shell is 0
Gravitational Potential outside the Spherical Shell is V= -GM/r where r>R
Gravitational Potential inside a Solid Sphere is V= -GM(3R2-r2)/2R3 where r<R
Potential of a thin ring on the axis at a distance r is V= -GM/R2+r2
Escape Velocity from a planet is v=2GM/R
Orbital Velocity of a satellite is v=GM/r where r>R
Time Period of a satellite is T=2*rr/GM
Potential Energy of a point mass at a distance r from the center of object is U= -GMm/r
Kinetic Energy of a satellite is K=GMm/2r
Mechanical Energy of a satellite is E= -GMm/2r
Kepler’s 3rd Law of Planetary Motion is T2=ka3 where a is the length of semi-major axis
Physics Formulas for JEE Mains: Solid Mechanics
Candidates can refer to the below information to know the formulas covered in Solid Mechanics:
Stress is the Ratio of Internal Restoring Force per unit Area of Cross-Section
Strain is the Ratio of change in size of the object to its original size
Hooke’s Law within elastic limit is StressStrain
Young’s Modulus Y=( F/A )/( L/L )
Increment in length due to its own weight L=gl2/2Y
Bulk Modulus = -P/( V/V )
Compressibility is the reciprocal of Bulk Modulus
Modulus of Rigidity =(F/A)/
Poisson’s Ratio =Lateral Strain/Longitudinal Strain= -(D/D)(L/L)
Work Done on a wire is W=(1/2)*Stress*Strain*Volume=FL/2
Physics Formulas for JEE Mains: Fluid Mechanics
The following are the formulas covered in Fluid Mechanics:
Mass Density is =MassVolume
Specific Weight is WeightVolume=g
Relative Density is Density of LiquidDensity of Pure Water at 4OC
Density of a mixture with variable Volume is =k=1nmkk=1n( mk/k )
Density of a mixture with variable Mass is =k=1nVkkk=1nVk
Pressure P=Normal ForceArea
Difference of Pressure in depth h is P=hg
Gauge Pressure at depth h of a liquid when placed in an elevator is P=h( ga )
Gauge Pressure between two points on same level at a distance of l when the liquid is accelerated by a is P=la
Rotating Cylinder along the length and passing through the center, th extra height is h=(r)2/2g
Pascal’s Law: F1A1=F2A2
Absolute Pressure=Atmospheric Pressure+Gauge Pressure
Atmospheric Pressure is Patm=101325 N/m2
Buoyant Force is the Weight of Displaced Fluid, FB=Vg
Equation of Continuity is A1v1=A2v2
Bernoulli’s Theorem is P+v2/2+gh=Constant
Principle of Venturimeter is v=A22gh/( A12-A22 )
Velocity of Efflux is v=2gh
Horizontal Range of Efflux is R=2h(H-h)
Surface Tension is Force per unit Length, T=F/l
Surface Energy is S=TA
Excess Pressure for water droplet is 2T/R
Excess Pressure for soap bubble is 4T/R
Height of Capillary Rise h=2T/rg
Height of Capillary Rise after correction h=[ 2T/rg ]-(r/3)
Newton’s Law of Viscosity is F=A( dv/dx )
Stoke’s Law is F=6rv
Poiseuille’s Formula is Q=pr4/( 8L )
Terminal Velocity is vT=2r2(-)g/9
Reynold’s Number is Re=vd/
Physics Formulas for JEE Mains: Thermal Physics and Thermodynamics
Candidates can refer to the below information to know the formulas covered in Thermal Physics and Thermodynamics:
Linear Expansion l=l0(1+T)
Areal Expansion A=A0(1+T)
Volume Expansion V=V0(1+T)
Fractional Change in Time Period of a Simple Pendulum is T/2
Thermal Strain l/l=T
Thermal Stress F/A=YT
Coefficient of Volume Expansion in Gases is =1/T
Heat Capacity of a body is H=Q/T
Specifc Heat Capacity is s=Q/mT
Molar Heat Capacity is Q/nT
Latent Heat L=Q/m
Rate of Heat Flow is dQdt= -KAdTdx
Thermal Resistance RT=l/KA
Coefficient of Thermal Conduction in Series Connection is K=i=1nlii=1nli/Ki
Coefficient of Thermal Conduction in Parallel Connection is K=i=1nKiAii=1nAi
Stefan-Boltzmann’s Law says I=eT4 where I is the Intensity and e[0, 1]
Prevost’s Theory of Heat Enrgy Exchange is Inet=e( T4-T04 )
Newton’s law of Cooling is -dT/dt(T-T0) or T=T0+(Ti-T0)(-kt)
Newton’s Law of Cooling for small temerature difference is T1-T2t=k[T1+T22-T0]
Wien’s Displacement Law max=b/T where b2.8910-3mK
Solar Constant S=(RST2/r)2
Mayer’s Formula CP=Cv+R
Average Distance between two consecutive collisions is =12d2n
Mixture of Non-Reacting Gases –
Molecular Weight Mmix=k=1NnkWkk=1Nnk
Specific Heat Capacity at constant Volume is sV=k=1Nnk(sV)kk=1Nnk
Specific Heat Capacity at constant Pressure is sV=k=1Nnk(sP)kk=1Nnk
n-1=n11-1+n22-1+n33-1+…+nkk-1
Molar Heat Capacity for any polytropic process is C=CV+R1-x
First Law of Thermodynamics is Qsupplied=Wby system+U
Work Done by the System is W=V1V2P dV
For Adiabatic Process PV=Constant and W=(P1V1-P2V2)/(-1)
For Isothermal Process PV=Constant and W=nRT(V2/V1)
For Isobaric Prcess W=nRT
Efficiency of a Carnot Cycle is =1-T1T2
Coefficient of Performance is =T2T1-T2
Isothrmal Bulk Modulus of Gases is = -VPV
Adiabatic Bulk Modulus of Gases is = -VPV
Physics Formulas for JEE Mains: Oscillations and Waves
The following are the formulas covered in Oscillations and Waves:
Angular Frequency =km
Equation for Linear SHM is d2xdt2+2x=0
Equation for Angular SHM is d2dt2+2=0
Displacement in SHM is x=A(t+)
Velocity of a particle in SHM is v=A(t+)=A2-x2
Acceleration of a particle in SHM is a= -A2(t+)= -2x
Kinetic Energy of a particle in SHM is K=kA22(t+)/2
Potential Energy ofa particle in SHM is U=kA22(t+)
Total Energy of a particle in SHM is E=K+U=(1/2)kA2
Time Period in a Spring Block System is T=2mk
Time Period in a Combined Spring Block System is T=2k where is the reduced mass
Time Period in a Series combination of springs is T=2mk where k is the effective Spring Constant, that is 1k=1k1+1k2+1k3+…+1kn
Time Period in a Series combination of springs is T=2mk where k is the effective Spring Constant, that is k=k1+k2+k3+…+kn
Time Period of a Simple Pendulum is T=2lg
Time Period of a Physics Pendulum is T=2lg where =Moment of Inertiaml2
Time Perod of a Conical Penduum is T=2l g
Time Period of a Tortional Pendulum is T=2Ik
Time Period for an SHM in a U-Tube Manometer is T=2hg where h is the height
Time Period of a particle in SHM in a tunnel inside te Earth is T=2Rg
Equation of a Damped Oscillation is d2xdt2+2x+bmv=0
Displacement due to Damped Oscillation is x=A(-bt/2m)(t+)
Angular Velocity in Damped Oscillation is =km-b24m2
Total Energy in Damped Oscillation is E=(1/2)kA2(-bt/m)
Equation of any wave in 2-D is 2yt2=v22yx2
Equation of a Plane Progressive Wve in 2-D is y=A(t-kx) where k=2/
Velocity of a wave is v=/k
Velocity of the particle is vP=y/t=A(t-kx)
vP= -v(dy/dx)
Particle Acceleration is 2y/t2= -A2(t-kx)
Relation between Phase Difference, Path Difference and Time Difference is 2==TT
Kinetic Energy per unit volume is (1/2)vP2=(1/2)2A22(t-kx)
Potential Energy per unit volume is (1/2)2A22(t-kx)
Total Energy per unit volume is 2A22(t-kx)
Power of a wave is P=(1/2)2A2vS where S is the Area of Cross-Section
Intensity of a wave is (1/2)2A2v
Speed of a transverse wave on string v=T/
Interference of two waves –For amplitude A=A12+A22+2A1A2
For constructive Interference, =n or =2n and Imax=(I1+I2)2
For intensity I=I1+I2+2I1I2
For Destructive Interference, =(2n+1) and Imin=(I1-I2)2
Degree of Hearing is (Imax /Imin )-1( Imax/Imin )+1100
Amplitude of Reflected Wave is Ar=2-12+1Ai where is the frequency
Amplitude of Trnasmitted Wave is At=222+1Ai
nth harmonic in stationary string wave is f=nv/2l (fixed at both ends)
(2k-1)th harmonic in stationary wave is f=(2k-1)v/4l (fixed at one end)
Velocity of Sound Wave with elasticity E is v=E/
Newton’s Formula for Sound Waves v=P/
Laplace Correction to Newton’s Fomula v=P/
Equation of a Pressure Wave is p=ABk(t-kx)
Frequency in a Closed End Organ Pipe is f=(2k-1)v/4l for (2k-1)th harmonic
Error Correction in Closed End Organ Pipe is f1=v/4(l+0.6R)
Frequency of an Open End organ Pipe is f=nv/2l for nth harmonic
Error Correction in Open End Organ Pipe is f1=v/2(l+1.2R)
Wavelength of a Resonating Tube is =2(l2-l1)
End Correction in a Resonating Tube is e=(l2-3l1)/2
Loudness of Sound (in dB) is =10(I/I0)
Doppler’s Effect f=v+v0v-vsf
Physics Formulas for JEE Mains: Electrostatics
Candidates can refer to the below information to know the formulas covered in Electrostatics:
Coulomb’s Law F=140q1q2r2
Principle of Supreposition F=F1+F2+F3+…+Fn
Electric Field E=F/q
Electric Field due to a point charge is E=140qr2r
Equilibrium of charges for an Equilateral Triangle is q= -q0/3
Equilbrium of charges for a Square is = -q0(22+1)/4
Equilbrium of two charges hanging from a point through thread T=mg and T=Fe
Electric Potential Va= –aEdr or E= -V
Electric Potential for a point charge is V=140qr
Electric Potential Energy of two charges u=140q1q2r
Electric Dipole Moment p=q2a where 2a is the total length of the dipole
Torque on an electric dipole in a uniform electric field is =pE
Potential Energy stored in a dipole in a uniform electric field is U= -pE
Electric Field at Axial Point is E=1402pr3
Electric Field at Equitorial Point is E=140-pr3
Electric Field at any point due to an electric dipole is E=140p1+32r3
Electric Potential at any point due to an electric dipole is V=140pr2
Total Potential Energy due to many charges is U=Uself+ij=1n140qi qjr
Electric Flux and Gauss’s Law =SEdA=qenclosed0
Electric Field due to a charged spherical shell when rR is E=140Qr2
Electric Field due to a charged spherical shell when r<R is E=0
Electric Field due to a non-conducting sphere when rR is E=140qr2
Electric Field due to a non-conducting sphere when r<R is E=140q rR3
Electric Potential due to a charged spherical shell when rR is V=140Qr
Electric Potential due to a charged spherical shell when r<R is V=140QR
Electric Potential due to a non-conducting spherical when rR is V=140Qr
Electric Potential due to a non-conducting spherical when r<R is V=140Q(3R2-r2)2R3
Electric Field due to a charged ring at Axial Point is E=140q x(x2+R2)3/2
Electric Potential due to a charged ring at Axial Point is V=140qx2+R2
Electric Field due to a charged infinite cylinder is E=1402r where rR and is the Linear Charge Density
Electric Field due to an infinite charged plane is E=/20 where is the Surface Charge Density
Energy Density in Elctric Field is uE=0E2/2
Electric Field just outside any conductor is E=/0
Physics Formulas for JEE Mains: Capacitance and Capacitors
The following are the formulas covered in Capacitance and Capacitors:
Capacitance C=Q/V
Capacitance of a Parallel Plate capacitors when Dielectric of thickness t is used is C=0Ad-(t-t/) where is the Dielectric Constant
Capacitance of an isolated sphere C=4R
Capacitance of a Spherical Capacitor is C=4 ab/(b-a)
Capacitance of a Parallel Plate Capacitor is C=A/d
Capacitance of a Parallel Plate Capacitor with different dielctrics is C=0Ap=1ntp/p
Capacitance of a cylindrical capacitor is C=2(b/a)
Capacitance of capacitors in series is 1C=1C1+1C2+1C3+…+1Cn
Capacitance of a capacitors in parallel is C=C1+C2+C3+…+Cn
Energy stored in charged capacitor is U=CV2/2=QV/2=Q2/2C
Common Potential du to sharing of charges between two capacitors is V=k=1nCkVkk=1nCk
Force of Attraction between two capacitor plates is F=Q2/(20A)
Physics Formulas for JEE Mains: Current Electricity
Candidates can refer to the below information to know the formulas covered in Current Electricity:
Charge I=Q/t or I=dq/dt
Charge Density J=I/A or I=JdA or J=E
Drift Velocity vd=E
Drift Current Id=neAvd
Resistivity =RA/l
Dependence of Resistance on Temperature R=R0(1+)
Ohm’s Law V=IR
Kirchhoff’s Current Law Iinwards=Ioutwards
Kirchhoff’s Voltage Law Voltage=0
Resistance in Series R=R1+R2+R3+…+Rn
Resistance in Parallel 1R=1R1+1R2+1R3+…+1Rn
EMF of a cell with its internal resistance is VAB=ER+r
Cells in Series Connection I=nER+nr
Cells in Parallel Connection I=ER+(r/m)
Cells in Series and Parallel Connection I=mER+(mr/n)
Principle of Wheatstone Bridge is PQ=RS
Meter Bridge Principle S=100-llR
Potentiometer Principle E1E2=l1l2
Shunt Resistance for Ammeter is S=IgRgI-Ig
Shunt Resistance for Voltmeter is S=VIg-G
Electrical Power is P=VI=V2/R=I2R
Joule’s Law of Heating W=VIt=I2Rt or W=0tI2R dt
Power for Series Combination 1P=1P1+1P2+1P3+…+1Pn
Power for Parallel Connection P=P1+P2+P3+…+Pn
Physics Formulas for JEE Mains: Magnetic Effects of Current and Magnetism
The following are the formulas covered in Magnetic Effects of Current and Magnetism:
Biot-Savart Law dB=4I( dlr )r2 or dB=4Idlr2
0=410-7H/m
For moving charge dB=4q(vr)r2
Magnetic Field due to current carrying straight conductor is B=0I4R(1+2)
Magnetic Field due to current carrying infinite wire is B=0 I2R
Magnetic Field due to circular wire carrying current (at center) is B=0 I2R
Magnetic Field due to circular wire carrying current (at axis) is B=0 IR22(x2+R2)3/2
Magnetic Field due to circular arc at its center is B=04IR
Magnetic Field due to infinite solid cylinder is B=042IrR2 where r<R
Magnetic Induction due to Solenoid is B=0nI where n=N/2R
Magnetic Field due to a current carrying sheet is B=0I/2
Ampere’s Law LBdl=0Ienclosed
Lorentz Force F=qE+q(vB)
When charged particle moves undeviated then v=E/B
Magnetic Force on a moving charge is F=q(vB) or F=q B v
Magnetic Force due to current carrying wire is F=I(lB) or F=I B l
Force per unit length of parallel wire carrying current is f=042I1I2d
Torque on a magnetic dipole is =mB where m is the magnetic moment of dipole
For a moving coil galvanometer I=k/NAB
Force on a magnetic dipole in a non-uniform magnetic field is |F|=|mBr|
Current produced by a rotating charge is I=q/2
Magnetic Moment due to a rotting charge is m=qR2/2
Magnetic Field at Axial Position of a magnetic dipole is B=042mr3
Magnetic Field at Equatorial Point of a magnetic dipole is B=04-mr3
Magnetic Field at any point due to a magnetic dipole is B=04m1+32r3
Magnetic Potential due to magnetic dipole is V=04m r2
Potential Energy of a magnetic dipole in a uniform magnetic field is U= -mB
Magnetic Induction B=H and Magnetic Permeability =B/H
Magnetic Susceptibility = -1
Curie-Weiss Law says m1T-TC for Ferromagnetic materials
F(magnetic)F(electric)=v2c2
Physics Formulas for JEE Mains: Electromagnetic Induction
Candidates can refer to the below information to know the formulas covered in Electromagnetic Induction:
Magnetic Flux =BA for uniform Magnetic Field
Magnetic Flux =BdA for variable Magnetic Field
Faraday’s Law of Electromagnetic Induction EMFd/dt
Lenz’s Law of Electromagnetic Induction EMF= -d/dt
EMF induced in a straight conductor in uniform Magnetic Field is EMF=Blv
EMF induced in a rotating rod is EMF=BL2/2
For Transformers EMFVoltage
Efficiency of a Transformer is =Output PowerInput Power
Magnetic Field due to Solenoid is B=nI
Self Inductance of a Solenoid is L=0n2AL
Growth of Current in L-R Circuit I=( EMFR )[ 1-( -Rt/L ) ]
Current Decay I=I0( -Rt/L )
Self Inductance L=/I
Self induced EMF is EMF= -L*dI/dt
Series combination of inductors L=L1+L2+L3+…+Ln
Parallel combination of inductors 1/L=1/L1+1/L2+1/L3+…+1/Ln
Physics Formulas for JEE Mains: Alternating Current and EM Waves
The following are the formulas covered in Alternating Current and EM Waves:
Iavg=0TI dt0T dt
IRMS=0TI2 dt0T dt
If V=V0(t) then Vavg=2V0/ and VRMS=V0/2
If I=I0(t) then Iavg=2I0/ and IRMS=I0/2
Impedance of an LCR Circuit is Z=R2+( XL-XC )2
Power Factor==R/Z
Energy in an LC Circuit is E=LI2/2
For Series LCR Circuit d2dt2+RLdqdt+qLC=V0L(t)
For Parallel LCR Circuit d2dt2+1RCddt+LC=V02C(t)
Poynting Vector S=(1/0)( EB )
Maxwell correction for Ampere’s Law is Bdl=0[ Ic+0( d/dt ) ]
Physics Formulas for JEE Mains: Ray Optics and Wave Optics
Candidates can refer to the below information to know the formulas covered in Ray Optics and Wave Optics:
Reflection in Vector Form is r=e-2(en)n
Number of images in inclined mirror is 3600/n
Reflection in Vector Form is r=e-2(en)n
Number of images in inclined mirror is 3600/n
Mirror Formula 1f=1u+1v
Transverse Magnification m=h2/h1= -v/u
Optical Power P=1/f
Law of Refraction in Vector Form is (en)r=0
Snell’s Law 21=ir
Lateral Shift is x=t(i-r)r
Apparent Shift is x=t(1-1/)
Critical Angle in Total Internal Reflection is iC=-1(r/i)
Angle of Deviation in Prism is =(i1+i2)-(r1+r2) and A=r1+r2
When =min then i1=i2 and r1=r2, therefore glass=[ (A+min)/2 ](A/2)
For small angles Prism, v-ry=v-r-1 where =(v+r)/2
For the Refraction at Spherical Surface 2v-1u=2-1R
Lens Makers Formula 1f=(-1)[1R1-1R2]
Lens Formula 1f=1v-1u
Magnification of Lens is m=v/u
Power of a Lens is P=1/f
For the combination of Lens placed in contact to each other 1f=1f1+1f2
Newton’s Formula for Lens f=Distance of Object from Focus*Distance of Image from Focus
Mirror Formula 1f=1u+1v
Transverse Magnification m=h2/h1= -v/u
For the Refraction at Spherical Surface 2v-1u=2-1R
Lens Makers Formula 1f=(-1)[1R1-1R2]
Lens Formula 1f=1v-1u
Magnification of Lens is m=v/u
Power of a Lens is P=1/f
For the combination of Lens placed in contact to each other 1f=1f1+1f2
Newton’s Formula for Lens f=Distance of Object from Focus*Distance of Image from Focus
Topic – 20: Physics Formulas for JEE Mains: Modern Physics
The following are the formulas covered in Modern Physics:
Energy of a Photon is E=h
Linear Momentum of a Photon is p=h/
Intensity of Light is I=P/A
The formula for Wave Number is =R[ n1-2-n2-2 ] where R is the Rydberg’s constant
For X-Rays min[ 12400/V ]A
Moseley’s Law for Characteristic Spectrum =a(Z-b)
Bragg’s Law for Diffraction n=2d
Mass Defect in nuclear Fusion is m=[ Mass of Reactants-Mass of Products ]
Law of Radioactive Decay N=N0(-kt) where k is the Decay Constant
Half-Life of a Radioactive material t=2/k
Pressure on perfectly reflecting surface is P=2I/c
Pressure on perfectly absorbing surface is P=I/c
Einstein’s Photoelectric Equation is h=K+W0
Stopping Potential V=Kmax/e
De Broglie wavelength =h/mv
Kinetic Energy if a particle is K=p2/2m
Momentum of a particle is 2mK
For Bohr Atomic Model, mvr=nh/2
Radius of nth Circular Orbit is r=[ 0.529 n2/Z2 ] A
Energy of an electron in nth orbit is E= (-13.6 Z2/n2 )eV and Binding Energy is B= -E
Number of Nuclei left after n Half-Life is N=N0/2n
Mass-Energy Equivalence E=mc2
Radius of a Nucleus is R3=( 1.3*10-15 )3*A
Radioactive Disintegration with Succession N=(/k)( 1-(-kt) )
Physics Formulas for JEE Mains: Semiconductors and Communication System
Candidates can refer to the below information to know the formulas covered in Semiconductors and Communication System:
Form Factor f=IRMSIDC
Form Factor for Half Wave Rectifier is /2
Form Factor for Full Wave Rectifier is /22
Number of Electrons reaching from Valence Band to Conduction Band is n=AT3/2exp(- E/2kT )
Mass-Action Law is n2=ne*nh
Conductivity =ne( e+h )
Ripple Factor is r=IACIDC
Ripple Factor for Half Wave Rectifier is r1.21
Ripple Factor for Half Wave Rectifier is r0.48
Rectifier Efficiency is n=PDCPAC
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FAQs on Physics Formulas for JEE Mains
The following are some of the most frequently asked questions on Physics formulas for JEE Mains:
Q: How are the Physics formulas useful for JEE Mains? Ans: Candidates use formulas to solve numerous problems asked in the JEE Mains question paper.
Q: What are the important Physics formulas for JEE Mains? Ans: The important Physics formulas for JEE Mains are given in the article above. Candidates are requested to go through it.
Q: Who conducts the JEE Main exam? Ans: The National Testing Agency (NTA), along with the Joint Apex Board (JAB) is conducting JEE Mains in two phases: June and July Sessions.
Q: Where can I find the Physics formulas for JEE Mains? Ans: Class 11 and Class 12 NCERT Physics textbooks contain all the important physics formulas for JEE Mains.
Q: When will the JEE Mains exam be conducted? Ans: The first phase of JEE Mains to be held in January, 2025, whereas the second phase exam is to be conducted in April, 2025.
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