Abhijit Guha Solutions for Chapter: HCF and LCM, Exercise 2: Practice Problems Level 2

Some sweets are to be distributed among $16, 40$ and $70$ boys. Find the minimum number of sweets required to be distributed so that no sweet is left.

The LCM of two numbers is $12$ times their HCF. The sum of the HCF and the LCM is $403$. If one of the numbers is $93$, then the other number is:

Three numbers are in the ratio $2:3:4$ and their HCF is $12$. The LCM of the numbers is:

What is the least number, which when divided by the numbers $3, 5, 6, 8, 10$ and $12$ leaves in each case a remainder $2$, but when divided by $13$ leaves no remainder?

The least multiple of $13$, which on dividing by $4, 5, 6, 7$ and $8$, leaves remainder $2$ in each case is:

The HCF of three numbers is $24$. If these numbers are in the ratio of $35:55:77$, then what are these numbers?

The greatest number by which $1657$ and $2037$ are divided to give remainders $6$ and $5$, respectively is:

An electronic clock makes a beep after every $58$ seconds. Another makes after every $60$ seconds. They beeped together at $11.11 \mathrm{a}.\mathrm{m}.$. The time when they would beep together next is: