Embibe Experts Solutions for Chapter: Organic Chemistry- Some Basic Principles and Techniques, Exercise 4: Exercise-4

The most stable carbocation is:

Pyridine is less basic than triethylamine because:

The compound that reacts the fastest with methylamine is

Coniferyl alcohol is isolated from pine trees. The following observations were made about this alcohol :

I. It forms methylated product with Mel in presence of base.
Il. One equivalent of coniferyl alcohol reacts with two equivalents of benzoyl chloride.
III Upon ozonolysis, the coniferyl alcohol gives a product $\text{'}\mathrm{Y}\text{'}$ ($\mathrm{M}.\mathrm{F}$ ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{O}}_2$ ).

The increasing reactivity of the sites ($\mathrm{a}-\mathrm{d}$) in the following compound is ${\mathrm{S}}_{\mathrm{N}}1$ reaction is

The compound which would undergo a reaction with ammonia by the ${\mathrm{S}}_{\mathrm{N}}1$ mechanism is

The maximum number of moles of ${\mathrm{CH}}_3\mathrm{I}$ consumed by one mole of crixivan, a drug against $\mathrm{AlDS}$ is

The reactions from those given below that involve a carbocation intermediate are