Academic Experts Solutions for Chapter: Solution & Colligative Properties, Exercise 1: Exercise

When $20 \mathrm{g}$ of naphthenic acid $\left({\mathrm{C}}_{11}{\mathrm{H}}_8{\mathrm{O}}_2\right)$ is dissolved in $50 \mathrm{g}$ of benzene $\left({\mathrm{K}}_{\mathrm{f}}=1.72 \mathrm{K} \mathrm{kg} {\mathrm{mol}}^{-1}\right)$, a freezing point depression of $2 \mathrm{K}$ is observed. The van't Hoff factor $\left(\mathrm{i}\right)$ is x, then the value of 10x is

The Henry's law constant for the solubility of ${\mathrm{N}}_2$ gas in water at $298 \mathrm{K}$ is $1.0\times {10}^5 \mathrm{atm}$. The mole fraction of ${\mathrm{N}}_2$ in air is $0.8$. Determine the number of moles of ${\mathrm{N}}_2$ from air dissolved in $10$ moles of water of $298 \mathrm{K}$ and $5 \mathrm{atm}$ pressure. If answer is $\mathrm{x}\times {10}^{-4}$, then find the value of x.

Determine the freezing point (in ${}^{\circ }\mathrm{C}$) of a solution containing $0.1 \mathrm{g}$ of ${\mathrm{K}}_3\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]$ (Mol. Wt. $329$) in $100 \mathrm{g}$ of water $\left({\mathrm{K}}_{\mathrm{f}}=1.86 \mathrm{K} \mathrm{kg} {\mathrm{mol}}^{-1}\right)$.

$6.02\times {10}^{20}$ molecules of urea are present in $100 \mathrm{ml}$ of its solution. Determine the concentration of urea solution.

Two solutions of a substance (non electrolyte) are mixed in the following manner: $480 \mathrm{ml}$ of $1.5 \mathrm{M}$ first solution $+520 \mathrm{mL}$ of $1.2 \mathrm{M}$ second solution. Determine the molarity of the final mixture.

Benzene and toluene form nearly ideal solutions. At $20 °\mathrm{C}$, the vapour pressure of benzene is $75 \mathrm{torr}$ and that of toluene is $22 \mathrm{torr}$. Determine the partial vapour pressure of benzene at $20 °\mathrm{C}$ for a solution containing $78 \mathrm{g}$ of benzene and $46 \mathrm{g}$ of toluene in torr.

Density of a $2.05 \mathrm{M}$ solution of acetic acid in water is $1.02 \mathrm{g}/\mathrm{mL}$. Determine the molality(mol/kg) of the solution.

Round of the answer up to two places of decimal.

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290 \mathrm{mm}$ at $300 \mathrm{K}$. The vapour pressure of propyl alcohol is $200 \mathrm{mm}$. Determine the vapour pressure of ethyl alcohol is $0.6$, its vapour pressure (in $\mathrm{mm}$) at the same temperature would be: