EXERCISE 3

Author:Asok Kumar Das & Chittaranjan Dasgupta

Asok Kumar Das Physics Solutions for EXERCISE 3

Simple step-by-step solutions to EXERCISE 3 questions of Gauss' Law and its Application from A Text Book of PHYSICS PART 2 : CLASS 12. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from EXERCISE 3 with Hints & Solutions

EASY
12th West Bengal Board
IMPORTANT

The electric field just outside the surface of a conductor has a magnitude 10 kN/C and is directed away from the conductor. What is the surface charge density of the conductor? 

EASY
12th West Bengal Board
IMPORTANT

If E=6i^+3j^+4k^, calculate the electric flux through a surface of area 20 units in YZ -plane.

EASY
12th West Bengal Board
IMPORTANT

Calculate the number of electric line of force originating from a charge of 1C.

HARD
12th West Bengal Board
IMPORTANT

An electric flux of -5×103 Nm2C-1 Passes through a spherical Gaussian surface of radius 20 cm Due to the charge placed at its centre.

(i) Calculate the charge enclosed by the Gaussian surface,

MEDIUM
12th West Bengal Board
IMPORTANT

An electric flux of 6×103 Nm2C-1 passes through a spherical Gaussian surface of radius 10 cm due to the charge placed at its centre.

If the radius of the Gaussian surface is doubled how much flux would pass through the surface?

MEDIUM
12th West Bengal Board
IMPORTANT

A sphere of metal has a radius of 12 cm and carries a charge of 1.6×10-7C, distributed uniformly on its surface. Calculate the electric field intensity at a point inside the sphere.

MEDIUM
12th West Bengal Board
IMPORTANT

Calculate the electric field intensity at a point, when a sphere of metal has a radius of 12 cm And carries a charge of 1.6×10-7C, distributed uniformly on its surface.

(2) 18cm From the centre the sphere ?

HARD
12th West Bengal Board
IMPORTANT

From what distance should a 100 eV electron by fixed towards a large metal plate having a surface charge density of -2×10-6 cm-2, so that it just fails to strike the plate ? e=1.6×10-19C,ε0=8.85×10-12C2 N-1 m-2,1ev=1.6×10-19 J