B M Sharma Solutions for Chapter: Electric Potential, Exercise 5: DPP
B M Sharma Physics Solutions for Exercise - B M Sharma Solutions for Chapter: Electric Potential, Exercise 5: DPP
Attempt the practice questions on Chapter 3: Electric Potential, Exercise 5: DPP with hints and solutions to strengthen your understanding. Chapterwise/Topicwise Daily Practice Problems (DPP) Electrostatics and Current Electricity JEE Main & Advanced solutions are prepared by Experienced Embibe Experts.
Questions from B M Sharma Solutions for Chapter: Electric Potential, Exercise 5: DPP with Hints & Solutions
Both the ring and the conducting sphere are given the same charge . Determine the potential of the sphere. Assume that the centre of the sphere lies on the axis of the ring. Is it necessary that the charge on the ring be uniformly distributed to answer the above question?

A solid sphere of the radius has a cavity of radius The solid part has a uniform charge density and cavity has no charge. Find the electric potential at the point . Also, find the electric field (only magnitude) at a point inside the cavity.

A thin spherical conducting shell of the radius has a charge . Another charge is placed at the centre of the shell. The electrostatic potential at a point at a distance from the centre of the shell is

An arc of radius carries a charge. The linear density of charge is and the arc subtends an angle at the centre. What is the electric potential at the centre?

Two identical thin rings each of radius meters are coaxially placed at a distance meters apart. If coulomb and coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge from the centre of one ring to that of other is

If the electric potential of the inner shell is volt and that of the outer shell is volt, then the potential at the centre will be: (the shells are uniformly charged)

The potential difference between the centre and the surface of the sphere of radius and having uniform volume charge density within it will be

A mercury drop has potential on its surface. such drops combine to form a new drop. Find the potential on the surface of the new drop.
