B M Sharma Solutions for Chapter: Vectors, Exercise 47: Exercises
B M Sharma Physics Solutions for Exercise - B M Sharma Solutions for Chapter: Vectors, Exercise 47: Exercises
Attempt the practice questions on Chapter 3: Vectors, Exercise 47: Exercises with hints and solutions to strengthen your understanding. PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I solutions are prepared by Experienced Embibe Experts.
Questions from B M Sharma Solutions for Chapter: Vectors, Exercise 47: Exercises with Hints & Solutions
According to Newton's second law of motion, the resultant force on a particle is in the direction of acceleration of the particle.
Two forces and are acting on a particle as shown in the figure. The acceleration of the particle is along -axis. Find the value of (in newton).

In vector and be respectively equal to and . The unit vector parallel to is . Find the value of .

The two-point charges and are placed at and , respectively. They repel each other with a force of . The force on the due to is . Find the value of .

Four forces are acting on a particle. One force of magnitude is directed upward, another is directed East of North having the magnitude , third is directed in South-West direction is of magnitude and fourth force is . If the particle is in equilibrium. Find the value of .

If and are mutually perpendicular, Find the value of .

Find the volume of parallelepiped whose edges are represented by , and .

If , and are coplanar. Find the value of .

A force of in a particular direction must be applied to a block. For same reason. It is not possible to apply the force in that direction but two forces can be applied to and on either side of it in the same plane containing the given force. If the ratio of magnitude of forces as . Find the value of .
