Embibe Experts Solutions for Chapter: Electrostatics, Exercise 13: Exercise (Assertion & Reason)
Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electrostatics, Exercise 13: Exercise (Assertion & Reason)
Attempt the practice questions on Chapter 22: Electrostatics, Exercise 13: Exercise (Assertion & Reason) with hints and solutions to strengthen your understanding. Beta Question Bank for Medical: Physics solutions are prepared by Experienced Embibe Experts.
Questions from Embibe Experts Solutions for Chapter: Electrostatics, Exercise 13: Exercise (Assertion & Reason) with Hints & Solutions
A spherical conducting shell of inner radius and outer radius has a charge . A charge is placed at the centre of the shell. Find the surface charge densities on the inner and outer surface of the shell.

Assertion: On going away from a point charge or a small electric dipole, the electric field decreases at the same rate in both cases.
Reason: Electric field is inversely proportional to the square of the distance from the charge in all cases.

Assertion: Electric field inside conductor is zero in electrostatics.
Reason: Charge appears on surface of conductor.

Assertion: Heart can be considered as dipole.
Reason: Electric flux and electric field are same as dipole.

Assertion: Electric flux density is independent of medium.
Reason: It depends only on distance and charge.

Assertion: For a charged shell, potential inside shell depends only on the field inside shell.
Reason: Potential of shell may be determined only by the field outside.

Assertion :- Electrostatic energy does not follow superposition principle.
Reason :- Electrostatic energy density is a quadratic function.

Assertion: We cannot find electric field from Gauss's law for unsymmetrical charge distribution.
Reason: Gauss's law is not applicable for unsymmetrical charge distribution.
