Exercise (Analytical Questions)

In a vernier callipers, $N$ divisions of vernier scale coincide with $\left(N-1\right)$ divisions of main scale (in which $1$ division represents $1 \mathrm{mm}$). The least count of the instrument in $\mathrm{cm}$ should be

A vernier caliper have $20$ divisions on the vernier scale which coincide with $19$ divisions on the main scale. The least count of the instrument is $0.1 \mathrm{mm}$. The main scale divisions are of

$1 \mathrm{cm}$ on the main scale of vernier calipers is divided into $10$ equal parts. If $10$ divisions of vernier coincide with $8$ small divisions of the main scale, then the least count of the caliper is

A student measured the diameter of a wire using a screw gauge with least count $0.001 \mathrm{cm}$ and listed the measurements. The correct measurement is: