Odisha Board Solutions for Chapter: Electrochemistry, Exercise 1: QUESTIONS

Author:Odisha Board

Odisha Board Chemistry Solutions for Exercise - Odisha Board Solutions for Chapter: Electrochemistry, Exercise 1: QUESTIONS

Attempt the free practice questions on Chapter 3: Electrochemistry, Exercise 1: QUESTIONS with hints and solutions to strengthen your understanding. Bureau's Higher Secondary Chemistry Volume-2 solutions are prepared by Experienced Embibe Experts.

Questions from Odisha Board Solutions for Chapter: Electrochemistry, Exercise 1: QUESTIONS with Hints & Solutions

HARD
12th Odisha Board
IMPORTANT

Ag+ + e-   Ag ; Ecell° = +0.8 V and Zn2+ + 2e-   Zn ; Ecell° = -0.76 V. Calculate the cell potential for the reaction, 2Ag(s) + Zn2+(aq)  2Ag+(aq) +  Zn(aq) .

HARD
12th Odisha Board
IMPORTANT

Write down the working of mercury dry cell?

HARD
12th Odisha Board
IMPORTANT

Write down the working of nickel cadmium cell.

MEDIUM
12th Odisha Board
IMPORTANT

E° values for Fe3++3e-Fe and Fe2++2e-Fe are -0.036 V and -0.44 V respectively. Calculate E° and G° for the cell reaction Fe+2Fe3+3Fe2+.
 

EASY
12th Odisha Board
IMPORTANT

When salt spread on road to melt ice and snow during winter, corrosion of motor cars is a major problem, justify.

MEDIUM
12th Odisha Board
IMPORTANT

E° of Ag electrode is 0.8 V and solubility product of AgI is 1×10-16. Calculate the potential of Ag electrode at 25 °C in a saturated AgI solution in water.

HARD
12th Odisha Board
IMPORTANT

State and explain Faraday's laws of electrolysis. How many grams of Aluminium can be produced by the electrolysis of molten alumina with a current of 3 amperes for 10 minutes.

HARD
12th Odisha Board
IMPORTANT

Define and explain equivalent conductance and specific conductance. A 0.1 N solution of NaCl has a specific conductance of 0.00119 mhos cm-1. Find its equivalent conductance.