Simplify : 14 x 2 ÷ 2 y 2

Given, 14 x 2 ÷ 2 y 2 Dividing a monomial by another monomial, which is the basis for dividing a polynomial by a monomial.Group the monomial into numerical and variable factors. Divide the coefficients, and divide the variables by subtracting the exponents of each term. a m ÷ a n = a m - n a 0 = 1 So, 14 x 2 ÷ 2 y 2 Divide both top and bottom by 2 . = 14 x 2 ÷ 2 2 y 2 ÷ 2 = 7 x 2 y 2

Simplify : 8 x y ÷ 24 y

Given, 8 x y ÷ 24 y Dividing a monomial by another monomial, which is the basis for dividing a polynomial by a monomial.Group the monomial into numerical and variable factors. Divide the coefficients, and divide the variables by subtracting the exponents of each term. a m ÷ a n = a m - n a 0 = 1 So, 8 x y ÷ 24 y Divide both top and bottom by 8 . = 8 x y ÷ 8 24 y ÷ 8 = x 3

Simplify : 9 x ÷ 36 x y

Given, 9 x ÷ 36 x y Dividing a monomial by another monomial, which is the basis for dividing a polynomial by a monomial.Group the monomial into numerical and variable factors. Divide the coefficients, and divide the variables by subtracting the exponents of each term. a m ÷ a n = a m - n a 0 = 1 So, 9 x ÷ 36 x y Divide both top and bottom by 9 x . = 9 x ÷ 9 x 36 x y ÷ 9 x = 1 4 y

E M B I B E

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Algebra>Chapter 2 - Making Sense of Algebra>Exercise 2.4

Karen Morrison and Nick Hamshaw Solutions for Exercise 4: Exercise 2.4

Author:Karen Morrison & Nick Hamshaw

Karen Morrison Mathematics Solutions for Exercise - Karen Morrison and Nick Hamshaw Solutions for Exercise 4: Exercise 2.4

Attempt the practice questions from Exercise 4: Exercise 2.4 with hints and solutions to strengthen your understanding. Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition solutions are prepared by Experienced Embibe Experts.