Balance the following equations: a) CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + NaCl ( aq ) . b) MgCl 2 ( aq ) + Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + NaCl ( aq ) . c) ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + NaCl . d) PbNO 3 + NaCl → PbCl 2 ↓ + NaNO 3 .

The balanced chemical equation for the reaction is given below: When Calcium chloride is taken with Sodium sulphate, it reacts to form insoluble salt Calcium sulphate along with sodium chloride. CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + 2 NaCl ( aq ) . It is double displacement reaction. When magnesium chloride is taken with Sodium carbonate, it reacts to form insoluble salt magnesium carbonate along with sodium chloride. MgCl 2 ( aq ) + Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + 2 NaCl ( aq ) .It is a double displacement reaction. When zinc chloride is taken with Sodium carbonate, it reacts to form insoluble salt Zinc carbonate along with sodium chloride. ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + 2 NaCl . It is a type of double displacement reaction. When Lead nitrate is taken with Sodium chloride, it reacts to form insoluble salt Lead chloride along with sodium nitrate. Pb NO 3 2 + 2 NaCl → PbCl 2 ↓ + 2 NaNO 3 . It is a type of double displacement reaction.It is also known as Plumbous chloride.

Identify the spectator ions from the given reactions. a) CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + 2 NaCl ( aq ) . b) MgCl 2 ( aq ) + Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + 2 NaCl ( aq ) . c) ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + 2 NaCl . d) Pb NO 3 2 + NaCl → PbCl 2 ↓ + NaNO 3 .

A spectator ion is an ion that does not take part in the chemical reaction and is found in solution both before and after the reaction. From the below reaction, CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + 2 NaCl ( aq ) . Here Na + and Cl - are spectator ions. Ca + 2 + 2 Cl - + 2 Na + + SO 4 - 2 → CaSO 4 ( s ) ↓ + 2 Na + + 2 Cl - From the below reaction, MgCl 2 ( aq ) + Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + 2 NaCl ( aq ) . Here Na + and Cl - are spectator ions. Mg + 2 + 2 Cl - + 2 Na + + CO 3 - 2 → MgCO 3 ( s ) ↓ + 2 Na + + 2 Cl - From the below equation, ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + 2 NaCl Here Na + and Cl - are spectator ions. Zn + 2 + 2 Cl - + 2 Na + + CO 3 - 2 → ZnCO 3 ↓ + 2 Na + + 2 Cl - From the below reaction equation, Pb NO 3 2 + 2 NaCl → PbCl 2 ↓ + 2 NaNO 3 . Here Na + and NO 3 - are spectator ions. Pb + 2 + 2 NO 3 - + 2 Na + + 2 Cl - → PbCl 2 ↓ + 2 Na + + 2 NO 3 -

Write the ionic equations for the reactions . a) CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + 2 NaCl ( aq ) . b) MgCl 2 ( aq ) + 2 Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + 2 NaCl ( aq ) . c) ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + 2 NaCl d) PbNO 3 + NaCl → PbCl 2 ↓ + NaNO 3 .

A spectator ion is an ion that does not take part in the chemical reaction and is found in solution both before and after the reaction. From the below reaction, CaCl 2 ( aq ) + Na 2 SO 4 ( aq ) → CaSO 4 ( s ) ↓ + 2 NaCl ( aq ) . Ca + 2 + 2 Cl - + 2 Na + + SO 4 - 2 → CaSO 4 ( s ) ↓ + 2 Na + + 2 Cl - From the below reaction, MgCl 2 ( aq ) + 2 Na 2 CO 3 ( aq ) → MgCO 3 ( s ) ↓ + 2 NaCl ( aq ) . 2 Mg + + 2 Cl - + 2 Na + + CO 3 - 2 → MgCO 3 ( s ) ↓ + 2 Na + + 2 Cl - From the below equation, ZnCl 2 + Na 2 CO 3 → ZnCO 3 ↓ + 2 NaCl 2 Zn + + 2 Cl - + 2 Na + + CO 3 - 2 → ZnCO 3 ↓ + 2 Na + + 2 Cl - From the below reaction equation, Pb NO 3 2 + 2 NaCl → PbCl 2 ↓ + 2 NaNO 3 . Pb + + NO 3 - + Na + + Cl - → PbCl 2 ↓ + Na + + NO 3 -

E M B I B E

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q

RoseMarie Gallagher and Paul Ingram Solutions for Chapter: Acids and Bases, Exercise 7: Q

Author:RoseMarie Gallagher & Paul Ingram

RoseMarie Gallagher Chemistry Solutions for Exercise - RoseMarie Gallagher and Paul Ingram Solutions for Chapter: Acids and Bases, Exercise 7: Q

Attempt the free practice questions on Chapter 11: Acids and Bases, Exercise 7: Q with hints and solutions to strengthen your understanding. Complete Chemistry for Cambridge IGCSE® Second Edition solutions are prepared by Experienced Embibe Experts.

Questions from RoseMarie Gallagher and Paul Ingram Solutions for Chapter: Acids and Bases, Exercise 7: Q with Hints & Solutions

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 3

Choose two starting compounds you could use to make this insoluble salt Magnesium carbonate.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 3

Choose two starting compounds you could use to make this insoluble salt Zinc carbonate.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 3

Choose two starting compounds you could use to make this insoluble salt Lead chloride.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 4

Balance the following equations:

a) ${CaCl}_{2} (aq) + {Na}_{2} {SO}_{4} (aq) \to {CaSO}_{4} (s) ↓ + NaCl (aq)$ .

b) ${MgCl}_{2} (aq) + {Na}_{2} {CO}_{3} (aq) \to {MgCO}_{3} (s) ↓ + NaCl (aq)$ .

c) ${ZnCl}_{2} + {Na}_{2} {CO}_{3} \to {ZnCO}_{3} ↓ + NaCl$ .

d) ${PbNO}_{3} + NaCl \to {PbCl}_{2} ↓ + {NaNO}_{3}$ .

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 5

What is a spectator ion ?

HARD

Upper Secondary: IGCSE

IMPORTANT

Complete Chemistry for Cambridge IGCSE® Second Edition>Chapter 11 - Acids and Bases>Q>Q 5

Identify the spectator ions from the given reactions.

a) ${CaCl}_{2} (aq) + {Na}_{2} {SO}_{4} (aq) \to {CaSO}_{4} (s) ↓ + 2 NaCl (aq)$ .
b) ${MgCl}_{2} (aq) + {Na}_{2} {CO}_{3} (aq) \to {MgCO}_{3} (s) ↓ + 2 NaCl (aq)$ .
c) ${ZnCl}_{2} + {Na}_{2} {CO}_{3} \to {ZnCO}_{3} ↓ + 2 NaCl$ .
d) $Pb {({NO}_{3})}_{2} + NaCl \to {PbCl}_{2} ↓ + {NaNO}_{3}$ .