Exercise 2

Author:D.P. GUPTA, Preetima Bajpai & Sanjeev Kumar Jha

D.P. GUPTA Chemistry Solutions for Exercise 2

Simple step-by-step solutions to Exercise 2 questions of Carbonyl Compounds from Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from Exercise 2 with Hints & Solutions

EASY
VITEEE
IMPORTANT

Consider the following compounds:
I. HCHO II. CH3CHO III. CH3COCH3
What is the order of reactivity of these compounds?

MEDIUM
VITEEE
IMPORTANT

An organic compound, C3H6O does not give a precipitate with 2, 4 -dinitrophenylhydrazine reagent and does not react with metallic sodium. It could be:

MEDIUM
VITEEE
IMPORTANT

The most reactive compound towards the formation of cyanohydrin, on treatment with KCN, followed by acidification is:

MEDIUM
VITEEE
IMPORTANT

Compound 'A' (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product 'B' (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B', when treated with an aqueous solution of H2NCONHNH2HCl and sodium acetate, gives a product 'C'. Identify the structure of 'C'.

MEDIUM
VITEEE
IMPORTANT

An organic compound 'A' has a molecular formula C3H6O. It undergoes the iodoform test. When saturated with HCl, it gives 'B' of molecular formula C9H14O. 'A' and 'B', respectively are