A student builds the circuit, as shown, using a battery of negligible internal resistance. The EMF of cell is 12 V . The voltmeter has a resistance of 12 kΩ . Show that the reading on this voltmeter would be 9 . 5 V .

The R e q u , of the system is given as 1 R 1 = 1 400 + 1 12000 = 31 12000 R 1 = 12000 31 R e q u = R 1 + 100 R e q u = 12000 31 + 100 R e q u = 15100 31 The current is given circuit I = V R e q u = 12 15100 31 = 372 15100 = 25 1000 Applying Kirchhoff's Voltage Law in given loop, V c - i R 100 - V 12 K = 0 12 - 2 . 5 = V 12 K V 12 K = 9 . 5 V

This diagram shows a network of resistors connected to a cell of e.m.f. 6 . 0 V . Show that the resistance of the network of resistors is 40 Ω .

The equivalent resistance R e q u , of the given circuit is given as, The parallel equivalent of the resistance is given as, 1 R = 1 R 1 + 1 R 2 The series equivalent of the resistance is given as R = R 1 + R 2 1 R 1 = 1 40 + 1 60 1 R 1 = 3 + 2 120 = 5 120 = 1 24 R 1 = 24 Ω R 2 = R 1 + 96 = 24 + 96 = 120 Ω R 3 = 40 + 20 = 60 Ω 1 R e q u = 1 R 2 + 1 R 3 1 R e q u = 1 120 + 1 60 1 R e q u = 1 + 2 120 = 3 120 = 1 40 R e q u = 40 Ω

This diagram shows a network of resistors connected to a cell of e.m.f. 6 . 0 V . Calculate the current in the 60 Ω resistor.

The equivalent resistance R e q u , of the given circuit is given as, The parallel equivalent of the resistance is given as, 1 R = 1 R 1 + 1 R 2 The series equivalent of the resistance is given as R = R 1 + R 2 1 R 1 = 1 40 + 1 60 1 R 1 = 3 + 2 120 = 5 120 = 1 24 R 1 = 24 Ω R 2 = R 1 + 96 = 24 + 96 = 120 Ω R 3 = 40 + 20 = 60 Ω 1 R e q u = 1 R 2 + 1 R 3 1 R e q u = 1 120 + 1 60 1 R e q u = 1 + 2 120 = 3 120 = 1 40 R e q u = 40 Ω The current in given circuit is I = V R = 6 40 3 20 A From the parallel resistor voltage. I 2 R 2 = I 1 R 3 I 2 R 2 = I - I 2 R 3 I 1 + I 2 = I I 2 = I R 3 R 2 + R 3 = 6 40 × 60 120 + 60 = 6 × 60 40 × 180 = 1 20 A 60 I 3 = 40 I 4 60 I 3 = 40 I 2 - I 3 I 3 + I 4 = I 2 100 I 3 = 40 I 2 I 3 = 40 100 × 1 20 = 1 50 A

David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS

Author:David Sang & Graham Jones

David Sang Physics Solutions for Exercise - David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS

Attempt the practice questions on Chapter 9: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS with hints and solutions to strengthen your understanding. Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access solutions are prepared by Experienced Embibe Experts.

Questions from David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS with Hints & Solutions

EASY

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 8

This circuit contains batteries and resistors. You may assume that the batteries have negligible internal resistance.

Question Image

Calculate the current in the $12.00 Ω$ resistor.

EASY

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 9

Explain why an ammeter is designed to have a low resistance.

MEDIUM

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 9

A student builds the circuit, as shown, using a battery of negligible internal resistance. The reading on the voltmeter is $9.0 V .$

Question Image

The voltmeter has a resistance of $1200 Ω$ . Calculate the e.m.f. of the battery.

MEDIUM

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 9

A student builds the circuit, as shown, using a battery of negligible internal resistance. The EMF of cell is $12 V$ .

Question Image

The voltmeter has a resistance of $12 kΩ .$ Show that the reading on this voltmeter would be $9.5 V .$

EASY

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 9

Explain why a voltmeter should have as high a resistance as possible.

EASY

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 10

Explain what is meant by the resistance of a resistor.

MEDIUM

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 10

This diagram shows a network of resistors connected to a cell of e.m.f. $6.0 V .$

Question Image

Show that the resistance of the network of resistors is $40 Ω .$

MEDIUM

AS and A Level

IMPORTANT

Physics for Cambridge International AS & A Level Coursebook 3rd Edition Digital Access>Chapter 9 - Kirchhoff's Laws>EXAM-STYLE QUESTIONS>Q 10

This diagram shows a network of resistors connected to a cell of e.m.f. $6.0 V .$

Question Image

Calculate the current in the $60 Ω$ resistor.

David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS

David Sang Physics Solutions for Exercise - David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS

Questions from David Sang and Graham Jones Solutions for Chapter: Kirchhoff's Laws, Exercise 12: EXAM-STYLE QUESTIONS with Hints & Solutions

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