Dr. H.C. Srivastava and SUMEDHA SRIVASTAVA Solutions for Chapter: Solutions, Exercise 1: REVIEW EXERCISES

The molal freezing point constant of benzene is $4.90$ and its melting point is $5.51°\mathrm{C}$. A solution of $0.816 \mathrm{g}$ of a compound A when dissolved in $7.5 \mathrm{g}$ of benzene freezes at $1.59°\mathrm{C}$. Determine the molecular weight of A.

The latent heat of fusion of benzene is $30.25 \mathrm{cal}/\mathrm{g}$. $0.0802 \mathrm{g}$ of a substance when dissolved $13.03 \mathrm{g}$ of benzene lower the freezing point by $0.490°\mathrm{C}$. If pure benzene freezes at $5.4°\mathrm{C}$, calculate the molecular mass of the substance.

Calculate the osmotic pressure of $0.01 \mathrm{M}$ solution of cane sugar at $27°\mathrm{C}$. $\left(\mathrm{R}=0.0821 \mathrm{L} \mathrm{atm} {\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}\right)$

Calculate the concentration of a solution of glucose which is isotonic at the same temperature with a solution of urea containing $6.2 \mathrm{g}/\mathrm{L}$.

Osmotic pressure of a solution containing $7.0 \mathrm{g}$ of a protein in $100 \mathrm{mL}$ of solution is $20 \mathrm{mm} \mathrm{Hg}$ at $37 °\mathrm{C}$. Calculate the molecular mass of the protein. $\left(\mathrm{R}=0.0821 \mathrm{L} \mathrm{atm} {\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}\right)$

Calculate the freezing point of an aqueous solution of a non-electrolyte having osmotic pressure of $2.0 \mathrm{atm}$ at $300 \mathrm{K}$. $({\mathrm{K}}_{\mathrm{f}}=1.86 \mathrm{K} \mathrm{kg} {\mathrm{mol}}^{-1}, \mathrm{R}=0.0821 \mathrm{L} \mathrm{atm} {\mathrm{K}}^{-1}{\mathrm{mol}}^{-1})$

A solution of sucrose (mol.wt.$342$) is prepared by dissolving $68.4 \mathrm{g}$ of it per litre of solution. What is the osmotic pressure at $300 \mathrm{K}$? $\left(\mathrm{R}=8.314 \mathrm{k} \mathrm{Pa} {\mathrm{dm}}^3 {\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}\right)$

Osmotic pressure of a solution containing $2 \mathrm{g}$ of a protein (soluble in water) per $300 {\mathrm{cm}}^3$ of the solution is $20 \mathrm{mm} \mathrm{Hg}$ at $27 °\mathrm{C}$. Calculate the molecular mass of protein. $\left(\mathrm{R}=0.0821 \mathrm{L} \mathrm{atm} {\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}\right)$