A farmer moves along the boundary of a rectangular field ABCD as shown in the figure. He takes 4 minutes to travel across each side. Is the motion of this farmer uniform or non-uniform? Find his average speed over one complete round of the field.

The average speed of a moving object is defined as the total distance covered by it is divided by the total time taken. It is a scalar quantity. In this case, it takes the farmer 4 minutes to travel around each side of the rectangular shape field. The distances travelled on each side will now be calculated as follows: Given distances are- AB = 80 m BC = 40 m CD = 80 m DA = 40 m The farmer's motion is non-uniform since the distances traveled on each side differ. The distances traveled at equal time intervals are not equal in non-uniform motion. Calculate the entire distance traveled and divide it by the total time taken to get the average speed for one complete round of the field. Total distance traveled = AB + BC + CD + DA Total distance traveled = 80 m + 40 m + 80 m + 40 m Total distance traveled = 240 m Total time taken = 4 minutes × 4 sides Total time taken = 16 min Now, we will convert the total time taken into seconds. Total time taken = 16 minutes × 60 seconds / minute Total time taken = 960 seconds Average speed = Total distance traveled Total time taken Average speed = 240 m 960 seconds Average speed = 0 . 25 m s - 1 The farmer's average speed over the full round of the field is therefore approximately 0 . 25 m s - 1 .

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The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know

Dr. K C Trikha and N K Sehgal Solutions for Chapter: Motion and Time, Exercise 1: Something To Know

Author:Dr. K C Trikha & N K Sehgal

Dr. K C Trikha Science Solutions for Exercise - Dr. K C Trikha and N K Sehgal Solutions for Chapter: Motion and Time, Exercise 1: Something To Know

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Questions from Dr. K C Trikha and N K Sehgal Solutions for Chapter: Motion and Time, Exercise 1: Something To Know with Hints & Solutions

EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 5

In the given diagram of a simple pendulum, the time taken by the bob to move from X to Z is `t1' and from Z to O is `t2'. The time period of this simple pendulum is—
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EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 1

A farmer moves along the boundary of a rectangular field ABCD as shown in the figure. He takes $4$ minutes to travel across each side.
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Is the motion of this farmer uniform or non-uniform? Find his average speed over one complete round of the field.

EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 2

During rainy season, Shivam noted that the thundering sound of clouds was heard $6$ seconds after the lightening was seen by him. If speed of sound in air is $340 m s^{- 1}$ , find the distance of the point where the thundering sound was produced.

EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 3

How can we make a simple pendulum?

EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 3

A simple pendulum takes $10$ seconds to complete $5$ oscillations. Find the time period of this pendulum.

EASY

7th CBSE

IMPORTANT

The Living World A book of Science and Technology>Chapter 6 - Motion and Time>Something To Know>Q 4

Carefully examine the data given below for the motion of two different objects A and B. State whether the motion of these two objects is uniform or non-uniform.
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