Dr. SK Goyal Solutions for Chapter: Ellipse, Exercise 7: Multiple Choice II

The locus of extremities of the latus rectum of the family of ellipse $b^2{x}^2+y^2=a^2{b}^2$:

Equation of tangent to the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$ which cut off equal intercepts on the axes is :

If $\left(5, 12\right)$ and $\left(24, 7\right)$ are the focii of a conic passing through the origin, then the eccentricity of conic is-

The latus rectum of the ellipse $x^2{\tan }^2\alpha +y^2{\sec }^2\alpha =1$ is $\frac{1}{2}$ then $\alpha \left(0<\alpha <\pi \right)$ is equal to :

The distance of the point $\left(\sqrt{6}\cos \theta ,\sqrt{2}\sin \theta \right)$ on the ellipse $\frac{x^2}{6}+\frac{y^2}{2}=1$ from the centre is $2$, if :

In the ellipse $25x^2+9y^2-150x-90y+225=0:$

Equation of tangent to the ellipse $x^2/9+y^2/4=1$ which cut off equal intercepts on the axes is :

The points where the normals to the ellipse $x^2+3y^2=37$ be parallel to the line $6x-5y=2$: