Compare the following pair of numbers : 13 . 56 × 10 12 , 97 . 56 × 10 11

Given: 13 . 56 × 10 12 , 97 . 56 × 10 11 Let us write the number in standard from. A number in scientific notation is given as the product of a number (integer or decimal) and a power of 10 . We move the decimal place forward or backward until we have a number between 1 and 10 . Then we add a power of ten that tells how many places you moved the decimal forward or backward. That is, 13 . 56 × 10 12 = 13 × 10 1 × 10 12 = 1 . 356 × 10 13 97 . 56 × 10 11 = 9 . 756 × 10 1 × 10 11 = 9 . 756 × 10 12 Now, let us compare the numbers, 1 . 356 × 10 13 > 9 . 756 × 10 12 Hence, 13 . 56 × 10 12 is greater than 97 . 56 × 10 11 .

Compare the following pair of numbers : 5 . 35 × 10 80 , 0 . 536 × 10 81

Given: 5 . 35 × 10 80 , 0 . 536 × 10 81 Let us write the number in standard from. A number in scientific notation is given as the product of a number (integer or decimal) and a power of 10 . We move the decimal place forward or backward until we have a number between 1 and 10 . Then we add a power of ten that tells how many places you moved the decimal forward or backward. That is, 5 . 35 × 10 80 = 5 . 35 × 10 80 0 . 536 × 10 81 = 5 . 36 10 × 10 81 = 5 . 36 × 10 80 Now, let us compare the numbers, 5 . 36 × 10 80 > 5 . 35 × 10 80 Hence, 5 . 35 × 10 80 is less than 0 . 536 × 10 81 .

Compare the following pair of numbers : 5 . 89 × 10 27 , 6735 × 10 24

Given: 5 . 89 × 10 27 , 6735 × 10 24 Let us write the number in standard from. A number in scientific notation is given as the product of a number (integer or decimal) and a power of 10 . We move the decimal place forward or backward until we have a number between 1 and 10 . Then we add a power of ten that tells how many places you moved the decimal forward or backward. That is, 5 . 89 × 10 27 = 5 . 89 × 10 27 6735 × 10 24 = 6 . 735 × 10 3 × 10 24 = 6 . 735 × 10 27 Now, let us compare the numbers, 5 . 89 × 10 27 < 6 . 735 × 10 27 Hence, 5 . 89 × 10 27 is less than 6735 × 10 24 .

Compare the following pair of numbers : 9 . 73 × 10 56 , 1 . 01 × 10 57

Given: 9 . 73 × 10 56 , 1 . 01 × 10 57 The given numbers is already in a standard form. You can compare two numbers written in scientific notation by looking at their powers of 10 . The number with the greater power of 10 will be the greater number. If two numbers have the same power of 10 , then compare the decimal numbers to determine the greater number. Now, let us compare the numbers, 9 . 73 × 10 56 < 1 . 01 × 10 57 Hence, 9 . 73 × 10 56 is less than 1 . 01 × 10 57 .

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Excellence in Mathematics>Chapter 3 - Powers>ASSIGNMENT 3.3

Dr. Sanjeev Verma and R.K. Tyagi Solutions for Chapter: Powers, Exercise 3: ASSIGNMENT 3.3

Author:Dr. Sanjeev Verma & R.K. Tyagi

Dr. Sanjeev Verma Mathematics Solutions for Exercise - Dr. Sanjeev Verma and R.K. Tyagi Solutions for Chapter: Powers, Exercise 3: ASSIGNMENT 3.3

Attempt the practice questions on Chapter 3: Powers, Exercise 3: ASSIGNMENT 3.3 with hints and solutions to strengthen your understanding. Excellence in Mathematics solutions are prepared by Experienced Embibe Experts.