Embibe Experts Solutions for Chapter: Three Dimensional Geometry, Exercise 1: TS EAMCET 2018 (04-May Shift-1)

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Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Three Dimensional Geometry, Exercise 1: TS EAMCET 2018 (04-May Shift-1)

Attempt the free practice questions on Chapter 30: Three Dimensional Geometry, Exercise 1: TS EAMCET 2018 (04-May Shift-1) with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Three Dimensional Geometry, Exercise 1: TS EAMCET 2018 (04-May Shift-1) with Hints & Solutions

MEDIUM
TS EAMCET
IMPORTANT

The position vectors of the points P and Q are respectively -2i¯-3j¯+k¯ and 3i¯+3j¯+2k¯. The ratio in which the point having position vector -92i¯-6j¯+12k¯ divides the line segment joining P and Q is

EASY
TS EAMCET
IMPORTANT

The centroid of a triangle with vertices A(3, 4, 5), B(6, 7, 2) and C(x, y, z) is (3, 2, 3) then x+y+z=

MEDIUM
TS EAMCET
IMPORTANT

The perpendicular distance from the origin to the plane containing the points having position vectors i^+2j^+3k^, 2i^+3j^-4k^, 3i^-4j^+5k^ is

EASY
TS EAMCET
IMPORTANT

A point on the plane determined by the points A(1, 1, -1), B(2, -1, 0) and C(-1, 0, 2) among the following is

EASY
TS EAMCET
IMPORTANT

The Cartesian equation of a plane parallel to the plane r·(2i^+3j^-4k^)=1 and at a distance of 2 units from it is

EASY
TS EAMCET
IMPORTANT

Suppose L1 and L2 are two lines having the direction ratios 1,-2,-2 and 0, 2, 1 respectively. If the direction cosines of a line perpendicular to both L1 and L2 are l, m, n then l+|m|+|n=

EASY
TS EAMCET
IMPORTANT

The shortest distance between the Skew lines r=(3i^+4j^-2k^)+λ(-i^+2j^+k^) and r=(i^-7j^-2k^)+μ(i^+3j^+2k^) is

EASY
TS EAMCET
IMPORTANT

If (2, -1, 2) and (K, -3, -5) are the triads of direction ratios of two lines and the angle between the lines is 60°, then