Embibe Experts Solutions for Chapter: Hydrocarbons, Exercise 4: Exercise-4

What is the value of $\mathrm{\Delta n}$ for combustion of one mole of benzene, when both the reactants and the products are gas at $298 \mathrm{K}$

Which of the following is unsaturated Hydrocarbon?

The shape of $2$-butene is:

The major product of the following reaction is

${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{C}\equiv \mathrm{CH}$ $\stackrel{\left(\mathrm{i}\right) {\mathrm{NaNH}}_2, \left(\mathrm{ii}\right) {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}}{\to }$

The best sequence of reactions to prepare $2-$heptanone is:

The compound $"\mathrm{X}"$ reacts with diborane followed by alkaline hydrogen peroxide to form compound $"\mathrm{Y}"$.$"\mathrm{Y}"$ on reaction with a mixture of sodium bromide in sulphuric acid followed by bromobenzene and sodium in ether gives $\mathrm{n}-$pentylbenzene, Compound $"\mathrm{X}"$ is:

The appropriate sequence of reactions for obtaining $2-$phenylbutanoic acid from benzene is

Terpinen$-4-\mathrm{ol}$ is an active ingredient in tea tree oil has the following structure

The correct observations for terpinen$-4-\mathrm{ol}$ is/are
$\mathrm{I}$. It rotates the plane of plane polarized light.
$\mathrm{II}$. It reacts with Baeyer's reagent to form form a triol
$\mathrm{III}$. On reaction with $\mathrm{NaBr}$ and ${\mathrm{H}}_2{\mathrm{SO}}_4$, it gives form a diobromo compound
$\mathrm{IV}$. On ozonolysis it gives a compound with molecular formula ${\mathrm{C}}_{10}{\mathrm{H}}_{18}{\mathrm{O}}_3$ ?