Embibe Experts Solutions for Chapter: Thermodynamics, Exercise 5: Exercise-5

Author:Embibe Experts

Embibe Experts Chemistry Solutions for Exercise - Embibe Experts Solutions for Chapter: Thermodynamics, Exercise 5: Exercise-5

Attempt the free practice questions on Chapter 4: Thermodynamics, Exercise 5: Exercise-5 with hints and solutions to strengthen your understanding. Alpha Question Bank for Engineering: Chemistry solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Thermodynamics, Exercise 5: Exercise-5 with Hints & Solutions

HARD
JEE Main/Advance
IMPORTANT

Two moles of an ideal gas are heated at a constant pressure of one atmosphere from 27°C to 127°C. If Cv,m=20+10-2TJK-1mol-1, q and ΔU for the process are, respectively:

HARD
JEE Main/Advance
IMPORTANT

Consider a classroom that is roughly 5m×10m×3m. Initially, t=27°C P=1 atm. There are 50 people in an insulated class losing energy to the room at the average rate of 150 Watt per person. How long can they remain in the class if the body temperature is 42°C and the person feels uncomfortable above this temperature? Heat capacity of air=(7/2)R.

MEDIUM
JEE Main/Advance
IMPORTANT

There are two samples of the same gas, initially under the similar initial state. Gases of both the samples are expanded. Ist  sample using reversible isothermal process and IInd  sample using reversible adiabatic process till the final pressures of both the samples becomes half of the initial pressure. Then:

EASY
JEE Main/Advance
IMPORTANT

In a laboratory, liquid in a thermally insulated container is stirred for one hr, by a mechanical linkage to an in the surrounding, for this process:

EASY
JEE Main/Advance
IMPORTANT

The efficiency of an hypothetical cell is about 84% which involves the following reaction:

As+B2+aqA2+aq+Bs; ΔH=-285 kJ

Then, the standard electrode potential of the cell will be (Assume as ΔS=0)

MEDIUM
JEE Main/Advance
IMPORTANT

The temperature coefficient, of the emf i.e. dEdT=-0.00065 volt deg-1 for the cell CdCdCl21 MAgCls|Ag at 25°C. Calculate the entropy changes ΔS298 K for the cell reaction, Cd+2AgClCd+++2Cl-+2Ag

HARD
JEE Main/Advance
IMPORTANT

The potential of the Daniell cell, ZnZnSO41 MCuSO41 MCu was reported by Buckbee, Surdzial and Metz as E°=1.1028-0.641×10-3T+0.72×10-5T2, where, T is the temperature in degree celsius. Calculate ΔS° for the cell reaction at 25°C:

HARD
JEE Main/Advance
IMPORTANT

ΔG=ΔH-TΔS and ΔG=ΔH+TdΔGdTp then dEcelldT is :