JEE Main - 10th April 2015
Embibe Experts Chemistry Solutions for Exercise - JEE Main - 10th April 2015
Simple step-by-step solutions to JEE Main - 10th April 2015 questions of Biomolecules from EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.
Questions from JEE Main - 10th April 2015 with Hints & Solutions
Number of cyclic tripeptides formed with amino acids and is:
Following tetrapeptide can be represented as
( are one letter codes for amino acids)
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Ketoses give Seliwanoff’s test faster than Aldoses.
Reason (R): Ketoses undergo -elimination followed by formation of furfural.
In the light of the above statements, choose the correct answer from the options given below:
A short peptide on complete hydrolysis produces moles of glycine , two moles of leucine and two moles of valine per mole of peptide. The number of peptide linkages in it are _____ .
A protein ‘’ with molecular weight of , on hydrolysis gives amino acids. One of these amino acid is
Compound , given a tetraacetate with and oxidation of with gives an acid, . Reduction of with gives isopentane. The possible structure of is :
Match List I and List II
List I | List II |
Test | Functional group / Class of Compound |
(A) Molisch's Test | (I)Peptide |
(B) Biuret Test | (II)Carbohydrate |
(C) Carbylamine Test | (III) Primary amine |
(D) Schiff's Test | (IV) Aldehyde |
Choose the correct answer from the options given below:
The correct representation in six membered pyranose form for the following sugar [] is