Embibe Experts Solutions for Chapter: Chemical Kinetics, Exercise 1: BITSAT 2017

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Embibe Experts Chemistry Solutions for Exercise - Embibe Experts Solutions for Chapter: Chemical Kinetics, Exercise 1: BITSAT 2017

Attempt the free practice questions on Chapter 11: Chemical Kinetics, Exercise 1: BITSAT 2017 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Chemical Kinetics, Exercise 1: BITSAT 2017 with Hints & Solutions

MEDIUM
BITSAT
IMPORTANT

Given the hypothetical reaction mechanism

AIBIICIIIDIV E and the rate as

Species formed Rate of its information
B 0.002 mol/h per mole of A
C 0.030 mol/h per mole of B
D 0.011 mol/h per mole of C
E 0.420 mol/h per mole of D

The rate determining step is

MEDIUM
BITSAT
IMPORTANT

For the chemical reaction

2O33O2, the reaction proceeds as follows

O3O2+O (Fast)

O+O32O2, (Slow)

the rate law expression should be given as

HARD
BITSAT
IMPORTANT

For a reversible reaction, AB, which one of the following statement is wrong from the given energy profile diagram?

Question Image

MEDIUM
BITSAT
IMPORTANT

Under the same reaction conditions, initial concentration of 1.386 mol dm-3 of a substance becomes half in 40 s and 20 s through first order and zero order kinetics, respectively. Ratio k1k0 of the rate of constants for first order k1 and zero order k0 of the reaction is

MEDIUM
BITSAT
IMPORTANT

The rate of a reaction triples when temperature changes from 200C to 500C. The energy of activation for the reaction is R=8.314JK-1 mol-1

EASY
BITSAT
IMPORTANT

Which of the following expression is correct for the rate of reaction given below ?

5Br-aq+BrO3-aq+6H+aq3Br2aq+3H2Ol

MEDIUM
BITSAT
IMPORTANT

For an endothermic reaction, where ΔH represent the enthalpy of reaction in kJ mol-1, the minimum value for energy of activation (for forward reaction) will be

MEDIUM
BITSAT
IMPORTANT

A graph is plotted between log K versus 1T for calculation of activation energy Ea. The correct plot is