Embibe Experts Solutions for Chapter: Solutions and Colligative Properties, Exercise 1: Maharashtra Board-2018

Derive van’t Hoff general solution equation for ‘n’ moles of solute.

What is freezing point of a liquid? The freezing point of pure benzene is 278.4 K. Calculate the freezing point of the solution when 2.0 g of a solute having molecular weight $100 \mathrm{g} {\mathrm{mol}}^{-1}$ is added to 100 g of benzene. (Kf of benzene = $5.12 \mathrm{K} \mathrm{kg} {\mathrm{mol}}^{-1}$ .)

Derive van’t Hoff general solution equation.

Define the following term:

Isotonic solution

Define the following term:

Hypertonic solution

Define the following term:

Hypotonic solution

Define: Osmotic pressure

Derive the mathematical expression between molar mass of a non-volatile solute and elevation of boiling point.
State and explain van’t Hoff-Avogardo’s law.