Embibe Experts Solutions for Chapter: Dual Nature of Radiation and Atomic Physics, Exercise 1: VITEEE 2017

The surface of a metal is illuminated with a light of wavelength $400 \mathrm{nm}$. The kinetic energy of the ejected photoelectrons was found to be $1.68 \mathrm{eV}$. The work function of the metal is $\left(hc=1240 \mathrm{eV} \mathrm{nm}\right)$,

Light of wavelength $\mathrm{500\; nm}$ is incident on a metal with work function $\mathrm{2.28\; eV.}$ The de Broglie wavelength of the emitted electron is:

In an electromagnetic wave

Which of the following are electromagnetic waves?

If the kinetic energy of a free electron doubles, it's de-Broglie wavelength changes by the factor

The ratio of the energies of the hydrogen atom in its first to second excited state is

A hydrogen atom is in the ground state. Then to get six lines in an emission spectrum, wavelength of the incident radiation should be

An electron makes a transition from an excited state to the ground state of a hydrogen-like atom. Then