Embibe Experts Solutions for Chapter: Electromagnetic Waves, Exercise 1: JEE Main - 1 February 2023 Shift 1

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electromagnetic Waves, Exercise 1: JEE Main - 1 February 2023 Shift 1

Attempt the free practice questions on Chapter 17: Electromagnetic Waves, Exercise 1: JEE Main - 1 February 2023 Shift 1 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Electromagnetic Waves, Exercise 1: JEE Main - 1 February 2023 Shift 1 with Hints & Solutions

EASY
JEE Main
IMPORTANT

All electromagnetic wave is transporting energy in the negative z direction. At a certain point and certain time the direction of electric field of the wave is along positive y direction. What will be the direction of the magnetic field of the wave at that point and instant?

MEDIUM
JEE Main
IMPORTANT

Match List I and List II

A Gauss’s Law in Electrostatics   I E·dl=-dϕBdt
B Faraday's Law II B·dA=0 
C Gauss’s Law in Magnetism III B·dl=μ0ic+μ00dϕEdt
D Ampere-Maxwell Law IV E·ds=q0

Choose the correct answer from the options given below :

EASY
JEE Main
IMPORTANT

Given below are two statements :

Statement I : Electromagnetic waves are not deflected by electric and magnetic field.

Statement II : The amplitude of electric field and the magnetic field in electromagnetic waves are related to each other as E0=μ0ε0B0.

In the light of the above statements, choose the correct answer from the options given below:

MEDIUM
JEE Main
IMPORTANT

A point source of light is placed at the centre of curvature of a hemispherical surface. The source emits a power of 24 W. The radius of curvature of hemisphere is 10 cm and the inner surface is completely reflecting. The force on the hemisphere due to the light falling on it is ______ ×10-8 N.

EASY
JEE Main
IMPORTANT

A point source of 100 W emits light with 5% efficiency. At a distance of 5 m from the source, the intensity produced by the electric field component is:

EASY
JEE Main
IMPORTANT

Match List I and List II

  List I   List II
A Microwaves I Physiotherapy
B UV rays II Treatment of cancer
C Infra-red rays III Lasik eye surgery
D X-rays IV Aircraft navigation

Choose the correct answer from the option given below:

EASY
JEE Main
IMPORTANT

Match the List-I with List-II:

  List I   List II
A Microwaves I Radioactive decay of the nucleus
B Gamma rays II Rapid acceleration and deceleration of electron in aerials
C Radio waves III Inner shell electrons
D X-rays IV Klystron valve

Choose the correct answer from the options given below:

EASY
JEE Main
IMPORTANT

The ratio of average electric energy density and total average energy density of electromagnetic wave is: