Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: MHT-CET 2017

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: MHT-CET 2017

Attempt the free practice questions on Chapter 16: Electrostatics, Exercise 1: MHT-CET 2017 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: MHT-CET 2017 with Hints & Solutions

EASY
MHT-CET
IMPORTANT

Which of the following molecules is a polar molecule?

MEDIUM
MHT-CET
IMPORTANT

The excess of pressure, due to surface tension, on a spherical liquid drop of radius R is proportional to

MEDIUM
MHT-CET
IMPORTANT

In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is 4 μF. Then its new capacity is

MEDIUM
MHT-CET
IMPORTANT

In a parallel plate capacitor, the capacity can be increased by decreasing

EASY
MHT-CET
IMPORTANT

Four capacitors of equal capacity have an equivalent capacitance C1 when connected in series and an equivalent capacitance C2 when connected in parallel. The ratio C2C1, is

EASY
MHT-CET
IMPORTANT

Three condensers of capacities C1C2, C3 are connected in series with a source of e.m.f. V. The potentials across the three condensers are in the ratio of

EASY
MHT-CET
IMPORTANT

The potential differences that must be applied across the parallel and series combination of 3 identical capacitors is such that the energy stored in them becomes the same. The ratio of potential difference in parallel to series combination is

HARD
MHT-CET
IMPORTANT

A series combination of N 1  each of capacityC1 is charged to a potential difference 3V. Another parallel combination of N 2 (each of capacity C 2 is charged to a potential difference V. The total energy stored in both the combination is the same. The value of C 1 in terms of C 2  is