The linear magnification for the image formed at the near point by a simple microscope can be obtained by using the relation
\n\n\n\n
Now according to our sign convention, is negative, and is equal in magnitude to Thus, the magnification is
\n\n\n\n
We will now find the magnification when the image is at infinity. In this case we will have to obtain the angular magnification. Suppose the object has a height . The maximum angle it can subtend, and be clearly visible (without a lens), is when it is at the near point, i.e. at a distance . The angle subtended is then given by
\n\n
\n\n
The angle subtended at the eye by the image when the object is at . From the relations
\n\n
We have the angle subtended by the image,
\n\n
\n\n
(when )
\n\n
Therefore, angular magnification is .
\n\n"},"comment":{"@type":"Comment","text":"The object is placed in between focus and optic centre of convex lens."},"encodingFormat":"text/markdown","learningResourceType":"Practice problem","suggestedAnswer":[],"text":"With a neat labelled diagram explain the formation of image in a simple microscope."},"name":"Quiz on Ray Optics and Optical Instruments","typicalAgeRange":"10-17","url":"https://www.embibe.com/questions/With-a-neat-labelled-diagram-explain-the-formation-of-image-in-a-simple-microscope./EM7458852"}
Embibe Experts Physics Solutions for Exercise - Telangana Board-2018
Simple step-by-step solutions to Telangana Board-2018 questions of Ray Optics and Optical Instruments from EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.
Questions from Telangana Board-2018 with Hints & Solutions
A concave mirror produces an image of a long vertical pin, placed from the mirror, at the position of the object. Find the focal length of the mirror (in ).