Embibe Experts Solutions for Exercise 9: Assignment

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Exercise 9: Assignment

Attempt the free practice questions from Exercise 9: Assignment with hints and solutions to strengthen your understanding. Gamma Question Bank for Engineering Physics solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Exercise 9: Assignment with Hints & Solutions

MEDIUM
JEE Main/Advance
IMPORTANT

Two charged metallic spheres of same size repel each other by a force F. They are now touched with each other and are then separated to same initial distance. Now the force of repulsion is F'. Which of following are possible ?

EASY
JEE Main/Advance
IMPORTANT

Which of the four particles contribute to the electric field at point P on the surface?

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EASY
JEE Main/Advance
IMPORTANT

Which of the four particles contribute to the net electric flux through the closed surface?

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EASY
JEE Main/Advance
IMPORTANT

Consider Gauss' law E·dA=qε0. Which of the following is not true?

HARD
JEE Main/Advance
IMPORTANT

Two infinite rods parallel to z-axis with linear charge density λ Passes through points (-a, 0, 0) and (a, 0, 0) , respectively. A charge particle having charge (-q) , and mass m Placed at origin is given slight displacement along y-axis. Time period of resulting motion is xπ3ε0ma28λq, Value of x is

MEDIUM
JEE Main/Advance
IMPORTANT

A non-conducting ring of mass m and radius R is charged as shown. The linear charge density for corresponding region shown is λ It is placed on tough horizontal surface. A uniform electric field E0i^ is switched on and the ring starts rolling without sliding. Angular velocity acquired by the ring when it turns through an angle of π2 is 16 rad s-1. Value of λE0m (in SI unit) is

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MEDIUM
JEE Main/Advance
IMPORTANT

A thin spherical shell of radius R carries uniform surface charge density σ. It is cut into two parts by a plane at a distance R2 from centre as shown. To hold two parts together force F from both side has to be applied. The minimum force F is 3πσ2R2nε0. Value of n, is

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MEDIUM
JEE Main/Advance
IMPORTANT

An infinitely large layer of charge of uniform thickness t is placed in existing uniform electric field. Presence of this charged layer so alters the electric field that it remains uniform on both the sides and assumes values E1 and E2 as shown in figure. If, E2=20 N C-1 Then component of external field in x-direction (in N C-1) is

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