Embibe Experts Solutions for Exercise 8: Assignment

A convex lens $(f=0.15 \mathrm{m})$ and a concave mirror (focal length $=0.3 \mathrm{m}$) are placed so that their optical axes $PQ$ and $RS$ are parallel to each other and separated by $0.6 \mathrm{cm}$ as shown. An lateral object $AB$ of height $1.2 \mathrm{cm}$ is placed on the optical axis $PQ$ at a distance of $0.2 \mathrm{m}$ from lens. If $A\text{'}B\text{'}$ is the image after refraction and reflection then choose the correct option(s).

A concave lens of focal length $f_1$ is placed in front of a converging mirror of focal length $f_2.$ Separation between lens and mirror is $X_0.$ A parallel beam of light having intensity $I_0$ is incident on lens and returns as a parallel beam from arrangement. If $I_R$ is the intensity of returning light beam and there is no absorption of light by the lens or mirror then

An object and a screen are fixed at a distance $d$ apart. When a lens of focal length $f$ is moved between the object and the screen, sharp images of the object are formed on the screen for two positions of lens. The magnifications produced at these two positions are $m_1$ and $m_2,$ then

A liquid of refractive index $1.62$ is placed in between two identical plano-convex lenses as shown in figure $A$ and $B.$ If refractive index of material of lens is $1.52$ and $F_A, F_B$ are the focal length of combination in arrangement $A$ and $B$ respectively, then

An object $O$ between two parallel (vertical) plane mirrors is approaching plane mirror $M_1$ as shown. If $V_1, V_2$ denote the magnitude of relative velocity of image with respect to object in mirror $M_1, M_2$ respectively and $V_{1, 2}$ denotes relative velocity of approach of the images formed due to direct reflection by each mirror, then

An equi-biconvex lens $(\mu =1.5)$ of focal length $20 \mathrm{cm}$ is cut into two parts and placed in contact as shown in the figure. A liquid of refractive index $1.3$ is filled between the two parts of lens. The equivalent focal length of the combination is (in $\mathrm{cm}$)

A ray of light is refracted through a glass sphere of refractive index $\sqrt{3}$ in such a way that it passes through the extremities of two radii which make an angle $120°$ with each other. If $\delta °$ is net deviation of ray, then value of $\delta$ is

A convex lens of focal length $20 \mathrm{cm}$ and another convex lens of focal length $40 \mathrm{cm}$ are placed co-axially. What should be the distance $d$ (in $\mathrm{cm}$) between lenses so that final image of object $O$ is formed on $O$ itself?