Embibe Experts Solutions for Exercise 3: Assignment

In $\mathrm{YDSE}$ two slits are placed $2 \mathrm{mm}$ from each other. Interference pattern is observed on a screen placed $1 \mathrm{m}$ from the plane of slit. What is the fringe width for a light of wavelength $600 \mathrm{nm} ?$ 

The first diffraction minima due to a single slit diffraction is at $30°$ for a light of wavelength $6000\backslash \mathrm{AA}.$ The width of slit is
 

A plane polarised light with intensity $I_0$ is incident on a polaroid with electric field vector making an angle of ${45}^{\text{'}\text{'}}$ with transmission axis of polaroid. The intensity of the transmitted light will be

The distance between the second maxima and fifth minima of a double-slit pattern is $5 \mathrm{mm}$ and the slits are separated by $0.30 \mathrm{mm}.$ If the screen is at a distance of $100 \mathrm{cm}$ from slits, then wavelength of the light used is

The ratio of resolving powers of an optical microscope for two wavelengths ${\lambda }_1=4500\stackrel{\circ }{A}$ and ${\lambda }_2=6000 \stackrel{\circ }{A},$ is
 

A beam of light of wavelength $400 \mathrm{nm}$ from a distant source falls on a single slit $2.00 \mathrm{mm}$ wide and the resulting diffraction pattern is observed on screen $2 \mathrm{m}$ away. The distance between the first dark fringes on either side of the central fringe is

Two polaroids are crossed to each other. Now one of them is rotated through $30°.$ The percentage of incident unpolarised light that transmits through the system will be

The distance between consecutive maxima and minima is given by