Embibe Experts Solutions for Chapter: Electromagnetic Induction and Alternating Currents, Exercise 2: Level 2
Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electromagnetic Induction and Alternating Currents, Exercise 2: Level 2
Attempt the practice questions on Chapter 16: Electromagnetic Induction and Alternating Currents, Exercise 2: Level 2 with hints and solutions to strengthen your understanding. Physics Crash Course JEE Main solutions are prepared by Experienced Embibe Experts.
Questions from Embibe Experts Solutions for Chapter: Electromagnetic Induction and Alternating Currents, Exercise 2: Level 2 with Hints & Solutions
The north pole of a magnet is brought near a metallic ring as shown in fig. The direction of induced current in the ring will be-

The flux of magnetic field through a closed conducting loop of resistance changes with time according to the equation where is time in seconds. Find heat produced in from to .

A metal conductor of length rotates vertically about one of its ends at angular velocity radians per second. If the horizontal component of earth's magnetic field is , then the emf developed between the two ends of the conductor is (in ):

Consider the situation shown in the figure. The wire is slide on the fixed rails with a constant velocity. If the wire is replaced by a semicircular wire; the magnitude of the induced current will

For a coil having , current flows through it is then the time (in second) at which emf becomes zero is-

A common transistor radio set requires for its operation. The source is constructed by using a transformer and a rectifier circuit, which are operated at on standard domestic supply. The number of turns of secondary coil are then the number of turns of primary are

An series circuit is connected to a source of alternating current. At resonance, the applied voltage and the current flowing through the circuit will have a phase difference of-

Power factor of an series circuit is . and that of a series circuit is . If the element ( and ) of the two circuits are joined in series the power factor of this circuit is found to be . The ratio of the resistance in the circuit to the resistance in the circuit is , find the value of .
