Kumar Mittal Solutions for Exercise 2: For DIFFERENT COMPETITIVE EXAMINATIONS

A parallel beam of light is incident from air at an angle $\alpha$ on the side $PQ$ of a right-angled triangular prism of refractive index $n=\sqrt{2}$. Light undergoes total internal reflection at the prism at the face $PR$ when $\alpha$ has a minimum value of $45°$. The angle $\theta$ of the prism is:

Monochromatic light is incident on a glass prism of angle $A$. If the refractive index of the material of the prism is $n$, a ray incident at an angle $\theta$, on the face $AB$ would get transmitted through the face $AC$ of the prism provided.

A beam of light consisting of red, green and blue colours is incident on a right-angled prism. The refractive index of the material of the prism for the above red, green and blue wavelengths are $1.39, 1.44$ and $1.47$, respectively. The prism will:

A thin prism having refracting angle $10°$ is made of glass of refractive index $1.42$. This prism is combined with another thin prism of glass of refractive index $1.7$. This combination produces dispersion without deviation. The refracting angle of the second prism should be:

The variation of refractive index of a crown glass thin prism with wavelength of the incident light is shown. Which of the following graphs is the correct one, if ${\delta }_m$ is the angle of minimum deviation?

A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is $\sqrt{3}$, then the angle of incidence is:

A ray $OP$ of monochromatic light is incident on the face $AB$ of prism $ABCD$ near vertex $B$ at an incident angle of $60°$ (see figure). If the refractive index of the material of the prism is $\sqrt{3}$, which of the following is (are) correct?

For an isosceles prism of angle $A$ and refractive index $n$, it is found that the angle of minimum deviation ${\delta }_m=A$. Which of the following options is/are correct?