Telangana Board Solutions for Chapter: Locus, Exercise 1: Exercise 1(a)

Find the equation of the locus of a point, the difference of whose distances from $(-5,0)$ and $(5,0)$ is $8$.

Find the equation of the locus of $P$, if $A=(4,0), B=(-4,0)$ and $|PA-PB|=4$.

Find the equation of the locus of a point, the sum of whose distances from $(0,2)$ and $(0,-2)$ is $6$.

Find the equation of the locus of $P,$ if $A=(2,3), B=(2,-3)$ and $PA+PB=8$.

$A(5,3)$ and $B(3,-2)$ are two fixed points. Find the equation of the locus of $P,$ so that the area of triangle $PAB$ is $9$.

Find the equation of the locus of a point, which forms a triangle of area $2$ with the points $A(1,1)$ and $B(-2,3)$.

If the distance from $P$ to the points $(2,3)$ and $(2,-3)$ are in the ratio $2:3,$ then find the equation of the locus of $P$.

$A(1,2), B(2,-3)$ and $C(-2,3)$ are three points. A point $P$ moves such that $P{A}^2+P{B}^2=2P{C}^2$. Show that the equation to the locus of $P$ is $7x-7y+4=0$.