Silver crystallizes in FCC lattice. If edge length of the cell is 4.07 × 10 - 8 c m and density is 10.5 g c m - 3 . Calculate the atomic mass of silver.

Given, Edge length of the cell ( a ) = 4.07 × 10 - 8 c m Density d = 10.5 g c m - 3 We also know that: the lattice is FCC type, the number of atoms per unit cell , Z = 4 N A = 6.022 × 10 23 m o le - 1 Using the relation d = Z M a 3 N A Therefore, M = da 3 N A Z = 10 .5 gcm - 3 x 4 .077 × 10 - 8 cm 3 × 6 .022 × 10 23 mole - 1 4 = 107.13 g mole - 1 Therefore, the atomic mass of silver = 107 .13 U

Copper crystallizes into FCC lattice with edge length 3.61 × 10 - 8 c m . Show that the calculated density is in agreement with its measured value of 8.92 g c m - 3 .

Given, Edge length a = 3.61 × 10 - 8 c m . The lattice is of FCC type. Therefore, the number of atoms per unit cell, Z = 4 Atomic mass, M = 63.5 g m o l - 1 We also know that, N A = 6.022 × 10 23 Applying the relation: d = Z M a 3 N A = 4 × 63 .5 g mol - 1 3 .61 × 10 - 8 cm 3 × 6 .022 × 10 23 mol - 1 = 8 . 97 g cm - 3 Hence, the calculated density 8.97 g c m - 3 is in agreement with its measured value which is 8.92 g cm - 3 .

E M B I B E

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions

Andhra Pradesh Board Solutions for Chapter: Solid State, Exercise 6: Questions

Author:Andhra Pradesh Board

Andhra Pradesh Board Chemistry Solutions for Exercise - Andhra Pradesh Board Solutions for Chapter: Solid State, Exercise 6: Questions

Attempt the practice questions on Chapter 1: Solid State, Exercise 6: Questions with hints and solutions to strengthen your understanding. Intermediate Second Year Chemistry solutions are prepared by Experienced Embibe Experts.

Questions from Andhra Pradesh Board Solutions for Chapter: Solid State, Exercise 6: Questions with Hints & Solutions

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 38

Derive Bragg's equation.

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 40

Silver crystallizes in FCC lattice. If edge length of the cell is $4.07 \times 10^{- 8} c m$ and density is $10.5 g c m^{- 3}$ . Calculate the atomic mass of silver.

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 41

Niobium crystallizes in body-centred cubic structure. If the density is $8.55 g c m^{- 3},$ calculate atomic radius of niobium using its atomic mass $93 U$ .

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 42

Copper crystallizes into FCC lattice with edge length $3.61 \times 10^{- 8} c m$ . Show that the calculated density is in agreement with its measured value of $8.92 g c m^{- 3}$ .

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 43

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

MEDIUM

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 44

Aluminium crystallizes in a cubic close-packed structure. Its metallic radius is $125 p m$ .

What is the length of the side of the unit cell?

HARD

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 44

Aluminium crystallises in a cubic close-packed structure. Its metallic radius is $125 pm$ . How many unit cells are there in $1.00 {cm}^{3}$ of aluminium?

MEDIUM

12th Andhra Pradesh Board

IMPORTANT

Intermediate Second Year Chemistry>Chapter 1 - Solid State>Questions>Q 45

How do you obtain the diffraction pattern for a crystalline substance?