Jose Paul Solutions for Chapter: Simple Equations, Exercise 3: EXERCISE 8.2
Jose Paul Mathematics Solutions for Exercise - Jose Paul Solutions for Chapter: Simple Equations, Exercise 3: EXERCISE 8.2
Attempt the practice questions on Chapter 8: Simple Equations, Exercise 3: EXERCISE 8.2 with hints and solutions to strengthen your understanding. Discovering Mathematics Book 8 solutions are prepared by Experienced Embibe Experts.
Questions from Jose Paul Solutions for Chapter: Simple Equations, Exercise 3: EXERCISE 8.2 with Hints & Solutions
A number is twice another number. When the larger is subtracted from , the result is more than the smaller is subtracted from . Find the numbers.

Banu is years older than Binu. In years Banu will be twice as old as Binu. Find their present ages.

Shiela is now years older than her younger brother Sanjay. Ten years from now Shiela will be twice as old as Sanjay. Find the present ages of each?

Jagdish has three more five-rupee notes than ten rupee notes. If he has worth of money by these two notes, how many of each kind of notes does he have?

Sanjiv has in ten paisa and paisa coins. If the ten paisa coins exceeds the number of twenty-five paisa coins by three, how many coins of each does he have?

Find three consecutive numbers whose sum is .

Find three consecutive numbers whose sum is .

Find three consecutive even numbers whose sum is .
