The daily wages of 45 workers in a factory are given below: Daily wages (in ₹ ) 300 375 450 525 600 Number of workers 6 8 9 12 10 Find the mean, median and mode of the given data.

First, we can find the median of the given data. The number of workers given is 45 , which is odd. Daily wages (in ₹ ) 300 375 450 525 600 Number of workers 6 8 9 12 10 Cumulative frequency 6 14 23 35 45 So, Median = n + 1 2 th observation = 45 + 1 2 th observation = 23 rd observation = 450 Hence, median = ₹ 450 We know that, the mean of the grouped data is, Mean = ∑ f i x i ∑ f i Daily wages (in ₹ ) x i 300 375 450 525 600 Number of workers f i 6 8 9 12 10 f i x i 1800 3000 4050 6300 6000 So, Mean = 1800 + 3000 + 4050 + 6300 + 6000 45 = 21150 45 = 470 Hence, mean = ₹ 470 Mode is the most frequently occurring data in the given information. Here, 525 is occurring 12 times. So, mode of the given data is ₹ 525 . Hence, the median is ₹ 450 , the mean is ₹ 470 and the mode is ₹ 525 .

The following table shows the marks obtained by 41 students of a class. Marks obtained 15 17 20 22 25 30 Number of students 2 5 10 12 8 4 Find the mean, median and mode of the given data.

First, we can find the median of the given data. The number of students given is 41 , which is odd. Marks obtained x i 15 17 20 22 25 30 Number of students f i 2 5 10 12 8 4 Cumulative frequency 2 7 17 29 37 41 So, Median = n + 1 2 th observation = 41 + 1 2 th observation = 21 st observation = 22 Hence, median = 22 We know that, the mean of the grouped data is, Mean = ∑ f i x i ∑ f i Marks obtained x i 15 17 20 22 25 30 Number of students f i 2 5 10 12 8 4 f i x i 30 85 200 264 200 120 So, Mean = 30 + 85 + 200 + 264 + 200 + 120 41 = 899 41 = 21 . 92 Hence, mean = 21 . 92 Mode is the most frequently occurring data in the given information. Here, 22 is occurring 12 times. So, mode of the given data is 22 . Hence, the median is 22 , the mean is 21 . 92 and the mode is 22 .

The following table shows the weight of 12 players. Weight 48 50 66 72 75 Number of players 4 3 2 2 1 Find the mean, median and mode of the given data.

First, we can find the median of the given data. The number of players given is 12 . which is even. So, Median = 1 2 n 2 th observation + n 2 + 1 th observation = 1 2 12 2 th observation + 12 2 + 1 th observation = 1 2 6 th observation + 7 th observation = 1 2 50 + 50 = 50 Hence, median = 50 We know that, the mean of the grouped data is, Mean = ∑ f i x i ∑ f i Weight x i 48 50 66 72 75 Number of players f i 4 3 2 2 1 f i x i 192 150 132 144 75 So, Mean = 192 + 150 + 132 + 144 + 75 12 = 693 12 = 57 . 75 Hence, mean = 57 . 75 Mode is the most frequently occurring data in the given information. Here, 48 is occurring 4 times. So, mode of the given data is 48 . Hence, the median is 50 , the mean is 57 . 75 and the mode is 48 .

E M B I B E

MATHEMATICS FOR CLASS 7>Chapter 21 - Collection and Organisation of Data (Mean, Median and Mode)>EXERCISE 21C

R S Aggarwal Solutions for Chapter: Collection and Organisation of Data (Mean, Median and Mode), Exercise 3: EXERCISE 21C

Author:R S Aggarwal

R S Aggarwal Mathematics Solutions for Exercise - R S Aggarwal Solutions for Chapter: Collection and Organisation of Data (Mean, Median and Mode), Exercise 3: EXERCISE 21C

Attempt the free practice questions on Chapter 21: Collection and Organisation of Data (Mean, Median and Mode), Exercise 3: EXERCISE 21C with hints and solutions to strengthen your understanding. MATHEMATICS FOR CLASS 7 solutions are prepared by Experienced Embibe Experts.