Solve the following equations and verify the solution: 3 4 y + 2 y = 1 2 + 4 y - 3

Given linear equation is: 3 4 y + 2 y = 1 2 + 4 y - 3 By simplifying the equation, we get, 11 y 4 = 4 y - 5 2 Subtracting 4 y on both sides, we get 11 y 4 - 4 y = - 5 2 11 y - 16 y 4 = - 5 2 - 5 y 4 = - 5 2 Dividing both sides by - 5 4 , we get y = - 5 2 × - 4 5 = 2 Hence, y = 2 is the solution to equation 3 4 y + 2 y = 1 2 + 4 y - 3 Verification: Substituting y = 2 in left-hand side of the equation LHS ⇒ 3 4 y + 2 y = 3 4 × 2 + 2 × 2 = 3 2 + 4 = 11 2 Substituting y = 2 in right-hand side of the equation RHS ⇒ 1 2 + 4 y - 3 = 1 2 + 4 × 2 - 3 = 1 2 + 5 = 11 2 Since LHS = RHS Hence, verified.

The rectangle below is made of unit squares. What are the possible ways of converting it into a square ?

In the figure below: The possible ways of converting it into a square are as follows: 1 . Remove one column of unit squares in the rectangle. 2 . Remove two columns and one row of the unit squares in the rectangle. 3 . Add one more row in the rectangle.

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Mathematics Textbook of Competency Based Questions for Class VIII>Chapter 5 - Squares and Square Roots>Exercise

Exercise

Author:NCERT

NCERT Mathematics Solutions for Exercise

Simple step-by-step solutions to Exercise questions of Squares and Square Roots from Mathematics Textbook of Competency Based Questions for Class VIII. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.