Exercise

In the fig., if $PA=15 \mathrm{cm}$, then perimeter of $△PQR$ is

Two circles touch externally at $A$. A common tangent $PQ$ to two circles touches the circles at $P$ and $Q$. Then the measure of $\angle PAQ$ is

The rectangle circumscribed about a circle is a square. Prove it.

What sort of a quadrilateral is formed by the tangents at the ends of two perpendicular diameters of a circle?

In the figure, if $PT$ is a tangent of the circle with centre $O$ and $\angle TPO=25°$, then the measure of $x$ is

The radius of a circle with centre $O$ is $6 \mathrm{cm}$. $P$ is a point at a distance $10 \mathrm{cm}$ from $O$. $PA$ and $PB$ are two tangents from $P$ to the circle. Then the area of the quadrilateral $APBO$ is

$AB$ is a chord of a circle with centre $O$ and $AP$ is a tangent. Prove that $\angle AOB=2\angle PAB$.

The tangents at $A$ and $B$ of a circle meet at $P$. If $\angle APB=56°$, then what is the value of $\angle PAB$?