Name: Acetaldehyde and Acetone
Uploaded: 2019-07-19
Duration: 3 min 15 s
Description: Do you know carbonyl compounds are used in medicines? In this video, you will be able to understand the important uses of the two most common compounds, acet...

Question

Match the common names given in Column I with the $IUPAC$ names given in
Column II.

Column I (Common names)	Column II (IUPAC names)
(i) Cinnamaldehyde	(a) Pentanal
(ii) Acetophenone	(b) $Prop - 2 - enal$
(iii) Valeraldehyde	(c) $4 - Methylpent - 3 - en - 2 - one$
(iv) Acrolein	(d) $3 - Phenylprop - 2 - enal$
(v) Mesityl oxide	(e) $1 - Phenylethanone$

Accepted Answer

(i) Cinnamaldehyde - $(d) 3 - phenylprop - 2 - enal$ :

The structure of Cinnamaldehyde is:

Here, a phenyl group is attached to a carbon atom at $3^{rd}$ position with respect to the functional group. A double bond is present between the $C_{2}$ and $C_{3}$ atoms. Thus, the $IUPAC$ name of Cinnamaldehyde is

$3 - Phenylprop - 2 - enal .$

(ii) Acetophenone - (e) $1 -$ Phenylethanone:

The structure of Acetophenone is:

Here, the functional group present in the above structure is a ketone. This ketone group is attached to one methyl group and one phenyl ring.

Thus, the $IUPAC$ name of Acetophenone is $1 -$ Phenylethanone.

(iii) Valeraldehyde - (a) Pentanal:

The structure of Valeraldehyde is:

${CH}_{3} {CH}_{2} {CH}_{2} {CH}_{2} CHO$

The functional group in this compound is an aldehyde. The number of carbon atoms in the longest chain is five. Thus, the $IUPAC$ name of Valeraldehyde is Pentanal.

(iv) Acrolein - (b) Prop $- 2 -$ enal:

The structure of Acrolein is:

${CH}_{2} = CH - CHO$

The functional group in this compound is aldehyde. The number of carbon atoms in the longest chain is three with one double bond between $C_{2}$ and $C_{3}$ atoms. Thus, the $IUPAC$ name of Acrolein is $Prop - 2 - enal$ .

(v) Mesityl oxide - (c) $4 - Methylpent - 3 - en - 2 one$

The structure of Mesityl oxide is:

$({CH}_{3})_{2} C = {CHCOCH}_{3}$

The functional group in this compound is a ketone. The number of carbon atoms in the longest chain is five with one double bond between $C_{3}$ and $C_{4}$ atoms. Thus, the $IUPAC$ name of Mesityl oxide is $4 - Methylpent - 3 - en - 2 - one$ .

Column I

(Common names)

Column II

(IUPAC names)

(i) Cinnamaldehyde (d) $3 - Phenylprop - 2 - enal$

(ii) Acetophenone (e) $1 - Phenylethanone$

(iii) Valeraldehyde (a) Pentanal

(iv) Acrolein (b) $Prop - 2 - enal$

(v) Mesityl oxide (c) $4 - Methylpent - 3 - en - 2 - one$

Column I (Acids)	Column II (IUPAC names)
(i) Phthalic acid	(a) $Hexane - 1, 6 - dioic acid$
(ii) Oxalic acid	(b) $Benzene - 1, 2 - dicarboxylic acid$
(iii) Succinic acid	(c) $Pentane - 1, 5 - dioic acid$
(iv) Adipic acid	(d) $Butane - 1, 4 - dioic acid$
(v) Glutaric acid	(e) $Ethane - 1, 2 - dioic acid$

Column I (Reactions)	Column II (Reagents)
$(i) Benzophenone \to Diphenylmethane$	$(a) {LiAlH}_{4}$
$(ii) Benzaldehyde \to 1 - Phenylethanol$	$(b) DIBAL — H$
$(iii) Cyclohexanone \to Cyclohexanol$	$(c) Zn (Hg) / Conc . HCl$
$(iv) Phenyl benzoate \to Benzaldehyde$	$(d) {CH}_{3} MgBr$

Column I (Example)	Column II (Reaction)
	(a) Friedel Crafts acylation
	(b) HVZ Reaction
	(c) Aldol condensation
	(d) Cannizaro's reaction
	(e) Rosenmund's reduction
	(f) Stephen's reaction

Matching Type

NCERT Chemistry Solutions for Exercise - Matching Type

Questions from Matching Type with Hints & Solutions

Learn and Prepare for any exam you want !