NCERT Solutions for Chapter: Electric Charges and Fields, Exercise 2: VSA

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

A metallic spherical shell has an inner radius ${\mathrm{R}}_1$ and outer radius ${\mathrm{R}}_2$. A charge $\mathrm{Q}$ is placed at the center of the spherical cavity. What will be surface charge density on $\left(\mathrm{i}\right)$ the inner surface, and $\left(\mathrm{ii}\right)$ the outer surface?

The dimensions of an atom are of the order of an Angstrom. Thus, there must be large electric fields between the protons and electrons. Why, then is the electrostatic field inside a conductor zero?

If the total charge enclosed by a surface is zero, does it imply that the electric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that the net charge inside is zero?

Sketch the electric field lines for a uniformly charged hollow cylinder shown in figure -

What will be the total flux through the faces of the cube as shown in figure with side of length $\mathrm{a}$. If a charge $\mathrm{q}$ is placed at-

$\left(\mathrm{a}\right) \mathrm{A}:$ A corner of the cube.
$\left(\mathrm{b}\right) \mathrm{B}:$Mid-point of an edge of the cube.
$\left(\mathrm{c}\right) \mathrm{C}:$Center of the face of the cube.
$\left(\mathrm{d}\right) \mathrm{D}:$Midpoint of B and C.