Natasha Awada, Paul La Rondie, Laurie Buchanan and, Jill Stevens Solutions for Chapter: Relationships in Space: Geometry and Trigonometry in 2D and 3D, Exercise 24: Exercise 11I

Author:Natasha Awada, Paul La Rondie, Laurie Buchanan & Jill Stevens

Natasha Awada Mathematics Solutions for Exercise - Natasha Awada, Paul La Rondie, Laurie Buchanan and, Jill Stevens Solutions for Chapter: Relationships in Space: Geometry and Trigonometry in 2D and 3D, Exercise 24: Exercise 11I

Attempt the free practice questions on Chapter 11: Relationships in Space: Geometry and Trigonometry in 2D and 3D, Exercise 24: Exercise 11I with hints and solutions to strengthen your understanding. Mathematics : Analysis and Approaches Standard Level Course Companion solutions are prepared by Experienced Embibe Experts.

Questions from Natasha Awada, Paul La Rondie, Laurie Buchanan and, Jill Stevens Solutions for Chapter: Relationships in Space: Geometry and Trigonometry in 2D and 3D, Exercise 24: Exercise 11I with Hints & Solutions

MEDIUM
Diploma
IMPORTANT

A flagpole is supported by three wires BA, BC and BD, as shown in this diagram.

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Show that the triangle ABC is not right angled.

EASY
Diploma
IMPORTANT

A dockyard crane ABC, is used to unload cargo from ships. AB=22.5m, AC=48m and angle ABC=46°. Find AC^B.

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MEDIUM
Diploma
IMPORTANT

A dockyard crane ABC, is used to unload cargo from ships. AB=22.5m, AC=48m and angle ABC=46°. Find the length of the lifting arm, BC.

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MEDIUM
Diploma
IMPORTANT

Two security cameras are positioned on the ceiling of a gym, 10m apart. One camera has an angle of depression of 50° to a point on the floor, and the other camera has an angle of depression of 60° to the same point. Calculate the height, h metres, of the gym.

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HARD
Diploma
IMPORTANT

A ship leaves Shanghai on a bearing of 030°. It sails a distance of 500 km to Jeju. At B, the ship changes direction to a bearing of 100°. It sails a distance of 320 km to reach Nagasaki. Calculate the bearing and distance for the ship to return from Nagasaki to Shanghai.

EASY
Diploma
IMPORTANT

Without actually calculating the size of the angle you will be able to say that AB^C is obtuse using cos(AB^C)=-1124, explain why you are able to do this.