Find the value by using suitable property. 365 × 105

Given, 365 × 105 We know that, When two whole numbers are multiplied, their product is also a whole number. If a a n d b are two whole numbers, then a × b is also a whole number. For example: 5 × 5 = 25 Therefore, 365 × 105 = 38325 Hence, required answer is 38325

Find the value by using suitable property. 439 × 99

Given, 439 × 99 We know that, When two whole numbers are multiplied, their product is also a whole number. If a a n d b are two whole numbers, then a × b is also a whole number. For example: 5 × 5 = 25 Therefore, 439 × 99 = 43461 Hence, required answer is 43461

Find 75 × 66 + 75 × 34 using the distributive property.

Given, 75 × 66 + 75 × 34 We know that, If a , b a n d c are three whole numbers, then a × b + c = a × b + a × c 75 × 66 + 75 × 34 = 75 × 66 + 34 = 75 × 100 = 7500 Hence, required answer is 7500

Use suitable property for calculating. 15 × 99

Given, 15 × 99 We know that, When two whole numbers are multiplied, their product is also a whole number. If a a n d b are two whole numbers, then a × b is also a whole number. The property used is Closure property of multiplication of whole numbers. For example: 5 × 5 = 25 Therefore, 15 × 99 = 1485 Hence, required answer is 1485

Use suitable property for calculating. 17 × 103

Given, 17 × 103 We know that, When two whole numbers are multiplied, their product is also a whole number. If a a n d b are two whole numbers, then a × b is also a whole number. The property used is Closure property of multiplication of whole numbers. For example: 5 × 5 = 25 Therefore, 17 × 103 = 1751 Hence, required answer is 1751

Use suitable property for calculating. 17 × 3 + 17 × 97

Given, 17 × 3 + 17 × 97 We know that, If a , b a n d c are three whole numbers, then a × b + c = a × b + a × c The property used is distributive property of multiplication over addition. 17 × 3 + 17 × 97 = 17 × 3 + 97 = 71 × 100 = 1700 Hence, required answer is 1700

Use suitable property for calculating. 15 × 45 + 15 × 5

Given, 15 × 45 + 15 × 5 We know that, If a , b a n d c are three whole numbers, then a × b + c = a × b + a × c The property used is distributive property of multiplication over addition. 15 × 45 + 15 × 5 = 15 × 45 + 5 = 15 × 50 = 750 Hence, required answer is 750

Use suitable property for calculating. 35 × 93 + 35 × 7

Given, 35 × 93 + 35 × 7 We know that, If a , b a n d c are three whole numbers, then a × b + c = a × b + a × c The property used is distributive property of multiplication over addition. 35 × 93 + 35 × 7 = 35 × 93 + 7 = 35 × 100 = 3500 Hence, required answer is 3500

E M B I B E

New Maths Buzz An Activity-based Course in Mathematics>Chapter 2 - Whole Numbers>Exercise

Dipali Sengupta and Bijo Thoms Solutions for Chapter: Whole Numbers, Exercise 2: Exercise

Author:Dipali Sengupta & Bijo Thoms

Dipali Sengupta Mathematics Solutions for Exercise - Dipali Sengupta and Bijo Thoms Solutions for Chapter: Whole Numbers, Exercise 2: Exercise

Attempt the free practice questions on Chapter 2: Whole Numbers, Exercise 2: Exercise with hints and solutions to strengthen your understanding. New Maths Buzz An Activity-based Course in Mathematics solutions are prepared by Experienced Embibe Experts.