Question

The steps to construct a $∆ P Q R$ with $Q R = 4 c m, P Q = 5 c m a n d Q R = 5.5 c m$ are given below in a jumbled order. Arrange the steps in the correct order.

(a) With $Q$ as centre and a radius equals to $5 cm$ , draw an arc.

(b) Draw a line segment $QR$ of $4 cm$ .

(c) Join $P$ and $Q$ , and $P$ and $R$ . $△ PQR$ is the required triangle.

(d) With $R$ as the centre and a radius of $5.5 cm$ , draw another arc intersecting the previous arc at $P$ .

Accepted Answer

The steps to construct a $∆ P Q R$ with $Q R = 4 c m, P Q = 5 c m a n d Q R = 5.5 c m$ are given in a jumbled order.

If three sides of a triangle are given, first we should consider one of its sides as the base and start the construction. Then, we need to draw the corresponding side lengths as arcs on the respective vertices. The meeting point of the arcs is joined with the end points of the line segment to obtain the required triangle.

The steps in the correct order is given by,

(b) Draw a line segment $QR$ of $4 cm$ .

(a) With $Q$ as centre and a radius equals to $5 cm$ , draw an arc.

(d) With $P$ as the centre and a radius of $R$ , draw another arc intersecting the previous arc at $P$ .

(c) Join $P$ and $Q$ , and $P$ and $R$ . $△ PQR$ is the required triangle.

Thus, the correct order is given by, (b) $\to$ (a) $\to$ (d) $\to$ (c).

Subject Experts Solutions for Chapter: Practical Geometry, Exercise 4: Let Us Try 11.2

Subject Experts Mathematics Solutions for Exercise - Subject Experts Solutions for Chapter: Practical Geometry, Exercise 4: Let Us Try 11.2

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