Electric Flux

A uniformly charged conducting sphere of $2.4 \mathrm{m}$ diameter has a surface charge density of $80 \mathrm{\mu C}/{\mathrm{m}}^2$. Find the charge on the sphere. What is the total electric flux leaving the surface of the sphere?

A point charge causes an electric flux of $-1.0\times {10}^3 {\mathrm{Nm}}^2{\mathrm{C}}^{-1}$ to pass through a spherical Gaussian surface of $10 \mathrm{cm}$ radius centered on the charge. What is the value of the point charge? (${\in }_0 = 8.854\times {10}^{-12} {\mathrm{N}}^{-1}{\mathrm{m}}^{-2}{\mathrm{C}}^2$)

A point charge causes an electric flux of $-1.0\times {10}^3 \frac{{\mathrm{Nm}}^2}{\mathrm{C}}$ to pass through a spherical Gaussian surface of $10 \mathrm{cm}$ radius centered on the charge.
If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?

A point charge of $2.0 \mathrm{\mu C}$ is at the center of a cubic Gaussian surface $9.0 \mathrm{cm}$ on edge. What is the net electric flux through the surface? (${\in }_0 = 8.854\times {10}^{-12}$)

A point charge $+10 \mathrm{\mu C}$ is a distance $5 \mathrm{cm}$ directly above the centre of a square of side $10 \mathrm{cm}$, as shown in the figure. What is the magnitude of the electric flux through the square? (Take, ${\in }_0 = 8.854\times {10}^{-12} \mathrm{C}$)

Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is $8.0 \times {10}^3 {\mathrm{Nm}}^2\mathrm{C}$
If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box? Why or Why not?

Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is $8.0\times {10}^3 {\mathrm{Nm}}^2{\mathrm{C}}^{-1}$. What is the net charge inside the box? Take, ${\in }_0 = 8.854\times {10}^{-12} {\mathrm{C}}^2{\mathrm{m}}^{-2}{\mathrm{N}}^{-1}$

Consider a uniform electric field $\mathrm{E} = 3\times {10}^3 \hat{\mathrm{i}} \mathrm{N}/\mathrm{C}$. What is the net flux of this uniform electric field through a cube of side $20 \mathrm{cm}$ oriented so that its faces are parallel to the coordinate planes?

Consider a uniform electric field $\mathrm{E}=3\times {10}^3 \hat{\mathrm{i}} \mathrm{N}/\mathrm{C}.$ What is the flux through the square of side $10 \mathrm{cm}$ if the normal to its plane makes a ${60}^{\mathrm{o}}$ angle with the x-axis?

Consider a uniform electric field $\overrightarrow{E}=3\times {10}^3 \hat{\mathrm{i}} \mathrm{N}/\mathrm{C}.$ What is the flux of this field through a square of $10 \mathrm{c}\mathrm{m}$ on a side whose plane is parallel to the $yz$ plane?