Magnetic Flux

A long conductor $AB$ lies along the axis of a circular loop of radius $R$. If the current in the conductor $AB$ varies at the rate of $I$ ampere/second, then the induced emf in the loop is

A conducting square loop of side I and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists perpendicular to the plane of the loop in fig. The current induced in the loop is -

The figure represents an area $A=0.5 {\mathrm{m}}^2$ situated in a uniform magnetic field $B=2.0 \mathrm{weber} {\mathrm{m}}^{-2}$ and making an angle of $60°$ with respect to the magnetic field. The value of the magnetic flux through the area would be equal to

Tesla is a unit of 

A coil of $10$ turns and area $4\times {10}^{-2} {\mathrm{m}}^2$ is placed in a uniform magnetic field of flux density ${10}^{-2} \mathrm{T}.$ If it is removed completely in $0.5 \mathrm{s},$ then the e.m.f. induced in the coil is

A coil of area $A=0.5 {\mathrm{m}}^2$ is situated in a uniform magnetic field $B=4.0 \mathrm{Wb} {\mathrm{m}}^{-2}$ and makes an angle of $60°$ with respect to the magnetic field as shown in figure. The value of the magnetic flux through the area A would be equal to

A coil of area $5 {\mathrm{cm}}^2$ having $20$ turns is placed in a uniform magnetic field of ${10}^3 \mathrm{gauss}$. The normal to the plane of the coil makes an angle $30°$ with the magnetic field. The flux through the coil is

A square coil ${10}^{-2} {\mathrm{m}}^2$ area is placed perpendicular to a uniform magnetic field of intensity ${10}^3 \mathrm{Wb} {\mathrm{m}}^{-2}$. The magnetic flux through the coil is  

A coil of radius $1 \mathrm{cm}$ and $100$ turns is placed in a magnetic field of ${10}^6$ $\mathrm{T}$ such that its plane makes an angle $30°$ with the field. The magnetic flux through the coil in S.I. unit is
 

A given wire is bent into a circular loop of radius $7 \mathrm{cm}$ and it is perpendicular to a magnetic field of  $1.0 \mathrm{T}$. Within $0.1 \mathrm{s}$, the loop is changed to a $100 \mathrm{cm}$ square and the field increases to$1.8 \mathrm{T}$. The e.m.f induced in the coil will be
 

A small loop of the area of cross-section ${10}^{-4} {\mathrm{m}}^2$ is placed at the centre of a bigger loop of radius $0.628 \mathrm{m}.$ A current of $10 \mathrm{A}$ is passed in the bigger loop. The smaller loop is rotated about its diameter with an angular velocity $\omega$. The magnetic flux linked with the smaller loop will be
 

A long solenoid has $1000$ turns and its area of cross-section is ${10}^{-4} {\mathrm{m}}^2$. If a magnetic induction of ${10}^{-2} \mathrm{T}$ is produced in it on passing a current of $1 \mathrm{A}$ through it, then the magnetic flux linked with it will be
 

A rectangular loop of area $0.4 {\mathrm{m}}^2$ is lying in a magnetic field of $4\times {10}^{-3}$ $\mathrm{T}$. If the plane of the loop is at right angles to the magnetic field, then the magnetic flux passing through the loops will be

A circular coil of diameter $10 \mathrm{cm}$ is placed in a magnetic field of induction $\sqrt{2}\times {10}^{-4} \mathrm{T}.$ The magnitude of flux linked with coil when the plane of coil makes an angle $45°$ with the field is

A magnetising field of $1600 \mathrm{A} {\mathrm{m}}^{-1}$ produces a magnetic flux of $2.4\times {10}^{-5} \mathrm{Wb}$ in a bar of iron of cross section $0.2 {\mathrm{cm}}^2.$ Then permeability of the bar is

The magnitude of magnetic induction at a point in a magnetic field of area $25 {\mathrm{cm}}^2$ and magnetic flux $5\times {10}^{-4} \mathrm{Wb}$ is

Magnetic flux is defined as number of magnetic lines of forces passing through a given area, such that angle between the lines of forces and surface is

The magnitude of magnetic strength at any point in magnetic field is,

$\mathrm{Wb}\times \frac{\mathrm{A}}{\mathrm{m}}$ is equal to

Find the magnetic flux linked with a square coil of side $0.1 \mathrm{m}$ placed perpendicularly to a uniform magnetic field of intensity ${10}^3 \mathrm{Wb} {\mathrm{m}}^{-2}$.